Thread: Making cin attach no value to an array when you push enter

  1. #1
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    Making cin attach no value to an array when you push enter

    How do you make cin to allow the program to continue to the next line, if there is no value to store in the array when you push enter?

    Example:

    Code:
    cout << "Enter a name: "
    cin >> X;
    cout << "Continuing the application anyhow."
    Program shows:

    Enter a name: // You push only the enter button, and want the program to continue instead of jumping rows.

  2. #2
    C++まいる!Cをこわせ!
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    Perhaps try cin.ignore after cin >> X.
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

  3. #3
    The larch
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    Perhaps:
    Code:
    cout << "Enter a name: "
    cin.get();
    cout << "Continuing the application anyhow."
    Assuming there is nothing left behind to read in cin.
    I might be wrong.

    Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
    Quoted more than 1000 times (I hope).

  4. #4
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    Quote Originally Posted by anon View Post
    Perhaps:
    Code:
    cout << "Enter a name: "
    cin.get();
    cout << "Continuing the application anyhow."
    Assuming there is nothing left behind to read in cin.
    It's in a for loop, and it dosent seem to work the way you put it. There are lots of cin and cout in the program, and the loop aswell.

  5. #5
    The larch
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    OK, so you want to accept empty strings as well.

    The simplest way is to use getline instead of >>
    Code:
    #include <iostream>
    #include <string>
    using namespace std;
    
    int main()
    {
        string s;
        while (getline(cin, s))
            cout << "\"" << s << "\"\n";
    }
    The difference, of course, is that this will read an entire line into a string, not up to first whitespace.

    Also, if there are lots of cin >> 's in the program, you should empty the input buffer after using >> and before using getline:
    Code:
    #include <limit>
    
    ...
         cin.ignore(numeric_limits<streamsize>::max(), '\n');
    Last edited by anon; 05-27-2008 at 04:21 PM.
    I might be wrong.

    Thank you, anon. You sure know how to recognize different types of trees from quite a long way away.
    Quoted more than 1000 times (I hope).

  6. #6
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    Quote Originally Posted by anon View Post
    OK, so you want to accept empty strings as well.

    The simplest way is to use getline instead of >>
    Code:
    #include <iostream>
    #include <string>
    using namespace std;
    
    int main()
    {
        string s;
        while (getline(cin, s))
            cout << "\"" << s << "\"\n";
    }
    The difference, of course, is that this will read an entire line into a string, not up to first whitespace.

    Also, if there are lots of cin >> 's in the program, you should empty the input buffer after using >> and before using getline:
    Code:
    #include <limit>
    
    ...
         cin.ignore(numeric_limits<streamsize>::max(), '\n');
    Thanks
    Last edited by Glauber; 05-27-2008 at 05:59 PM.

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