overloading with typedef

This is a discussion on overloading with typedef within the C++ Programming forums, part of the General Programming Boards category; Is it possible to make this work somehow (without adding an extra parameter or doing two separate functions)? Code: //I ...

  1. #1
    Registered User
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    overloading with typedef

    Is it possible to make this work somehow (without adding an extra parameter or doing two separate functions)?

    Code:
    //I didn't create this but am stuck using it
    typedef long jint;
    
    void doSomething(jint a)
    {
         ...do something with a jint...
    }
    
    void doSomething(long a)
    {
         ...do something with a different with a long...
    }

  2. #2
    Banned master5001's Avatar
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    Not a chance. Why would you want that anyway? Microsoft does similar in their API for equally unfathomable reasons.

    Example:
    Code:
    struct jint { long dummy; };
    struct kint { long dummy; };
    Thus making two incompatible types... But I know you have no control over jint. Why would you do such a thing?

  3. #3
    Captain Crash brewbuck's Avatar
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    Quote Originally Posted by 6tr6tr View Post
    Is it possible to make this work somehow (without adding an extra parameter or doing two separate functions)?
    You could make jint an actual class which does nothing except wrap the integer. That way it would be a distinct type from long. It would be a pain, with very little benefit. I'd just name the two functions two different names and live with the hackishness.

    typedefs are supposed to create aliases of types. They don't create distinct types which otherwise act exactly like each other. It's not the intention.

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