problem with printf!!!!

Hello everybody,
see this program

Code:

#include<stdlib>
#include<stdio>
#include<conio>
#include<iostream>

using namespace std;
int main()
 {
   int l;
   double x;
   float u[11][11];
   h=1.0/4.0 ;
   for (l=0; l<11;l++)
    {
      x=l*h;
      u[l][0]=1.0;
      printf("u=  %6.4f\n",u[l][0]); //line *
      printf("  %d    %d    %6.4f   %6.4f    %6.4f     \n",l,0,x,0,u[l][0]); //line **
    }
   getch();
 }//end program

the problem is that in the line *, puts the right value of u[l][0], it is one (1.0), but in the next line **, puts the value of u[l][0] as zero (0).

the problem is using printf?
Any suggest?

Bye Miguel.

I think you are just looking at the wrong column.

Anyway, note that your code should not even compile since <stdlib> should be <cstdlib>, <stdio> should be <cstdio>, <conio> should be <conio.h> but actually is not even needed as getch() can be replaced, and then h is not declared.

well, i'm working with Borland C++, it is not necessary to write ".h" at the end.
About the others libraries, i do not use for the moment.
I just took part of a program and posted it.

In any case, you are just looking at the wrong column.

If you disagree, post the smallest and simplest compilable code that demonstrates the problem. Oh, and do not use the Borland specific <conio>, and that means do not use getch().

o.k
but instead of getch(), tell me what to use?

but instead of getch(), tell me what to use?

How to keep a Windows console from closing.

i solved the problem,
thank you.