Question about operator overloading

Hallo,

I am doing some operator overloading and found something in a book I want to ask about:

Code:

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Point &operator = (const Point &p);

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Why is there a & in front of the operator keyword?

Thanks :)

Personally I prefer to put the & more to the left, like this:

Code:

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Point& operator = (const Point& p);

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...in which case it's easier to read that the operator returns a reference to a point (most likely itself, after the assignment)

If you were not actually confused by the syntax but rather was asking why the copy assignment operator returns a reference, the answer is that it is to facilitate operator chaining, e.g., a = b = c.

Ah, ok. Think I got it.

Working on a school assignment and dont want to use things I dont understand

Thanks :)