Hi All,
Can anyone please tell how to convert integral types like Integer into pointer types like Integer& ? (if we say Integer is a class).
This question has originated from following thread:
http://cboard.cprogramming.com/showt...617#post731617
PLEASE REPLY. ITS REALLY URGENT.
Thanks.
--Rohit
Yeah, right, that really deserves a quick response.Originally Posted by rohit99
Rules of the language mean that the name of a variable is inherently a reference to it if a reference is required: the conversion is implicit.
Integer& is a reference and not a pointer type.
To pass by reference, all you need to do is append & after the type in the receiving function and then pass the argument like normal. A reference is part of the type, so while originally "type", it becomes "type&" when you declare it as a reference.
Adding const only means that the receiving function cannot modify the variable. Nothing else. It's still passed by reference.Code:void foo(int& n) { } int main() { int n = 0; foo(n); return 0; }
Hi grumpy and Elysia,
Thanks for your replies.. I thnk I am sounding quite funny.. I knw Integer will b implicitly converted into Integer&.. n I didn't care about this while writing code bt I faced sum issues.. I guess not because of that..bt I panicked n thought issues were due to that conversion as compiler threw sum error sumwat similar to that..... I am sorry....
--Rohit
