bit o' fun

[The Brain]

#include <stdio.h>
 
int main(void) {
   int i = 5;
   /* Add a line of code here to make the printf() below output 5 */
   i = 8;
   printf("%d\n", i);
   return 0;
}

[JaWiB]

Umm:

#include <stdio.h>
 
int main(void) {
   int i = 5;
   #define printf printf("5\n");   
   i = 8;
   printf("%d\n", i);
   return 0;
}

[The Brain]

anyone come up with anything different..??

[valis]

Same idea:

#include <stdio.h>

int main(void)
{
	int i = 5;
	#define jab \
	i = 8;
	printf("%d\n", i);

	return(0);
}

or with two lines (under the assumption your x86)

#include <stdio.h>

int main(void)
{
	int i = 5;
	__asm add ebp,4
	i = 8;
	__asm sub ebp,4
	printf("%d\n", i);

	return(0);
}

[The Brain]

used more than one line..!!! :P

[kermit]

#include <stdio.h>

int main(void)
{
        int i = 5;

        if (i == 0)
                i = 8;

        printf("%d\n", i);
        return 0;
}

I know its kind of cheesey...

[Darryl]

#include <stdio.h>
 

int main(void) {
   int i = 5;
   while(false)
   i = 8;
   printf("%d\n", i);
   return 0;
}

[Quantum1024]

Some more x86 asm.

#include <stdio.h>
 
int main(void) {
   int i = 5;
a: __asm jmp a+12
   i = 8;
   printf("%d\n", i);
   return 0;
}

[pianorain]

Bah...why not?

#include <stdio.h>
 
int main(void) 
{
   int i = 5;
   return printf("5"),0;
   i = 8;
   printf("%d\n", i);
   return 0;
}

[kryptkat]

#include <stdio.h>
 
int main(void) {
   int i = 5;
   /* Add a line of code here to make the printf() below output 5 meow! 
   i = 8; */
   printf("%d\n", i);
   return 0;
}

[ahluka]

Originally Posted by Quantum1024

Some more x86 asm.

#include <stdio.h>
 
int main(void) {
   int i = 5;
a: __asm jmp a+12
   i = 8;
   printf("%d\n", i);
   return 0;
}

Does that mean "i = 8;" is 12 bytes long in the .exe?

[Raven Arkadon]

no,

a: __asm jmp a+12
i = 8;

is assumed to be 12 bytes long i = 8; AND the jmp