help me with void function

**ltcabral** · 03-06-2008

can anyone help me to transform this function to a void function, using the pointer address??

Code:

int main(){		

	...
	MYSQL	*p_connection;
	...
	p_connection = Initiate_mysql(p_connection);	
        ...
   
}

MYSQL* Initiate_mysql(MYSQL* p_connection){
	const char*	host = "xxxx";
	const char*	user = "xxxx";
	const char*	password = "xxxx";
	const char*	database = "xxxx";	

	p_connection = mysql_init(NULL);	

	if (!mysql_real_connect(p_connection,host,user,password,database,0,NULL,0)) {

		fprintf(stderr, "Failed to connect to p_database: Error: %s\n", mysql_error(p_connection));

	}
	return p_connection;

}

thx

**Elysia** · 03-06-2008

Initiate_mysql should simply take an additional MYSQL** as argument and you pass in p_connection as argument.

**matsp** · 03-06-2008

Originally Posted by Elysia

Initiate_mysql should simply take an additional MYSQL** as argument and you pass in p_connection as argument.

Or rather, the argument should be MYSQL ** instead of MYSQL *, and you need to pass the address of p_connection.

Edit: You will also need to dereference p_connection inside the function, of course.

--
Mats

**Elysia** · 03-06-2008

Hm. I missed that.

**ltcabral** · 03-06-2008

well thats what i changed considering ur advices... plz correct me if im wrong, cuz the program is compiling without errors, but giving me error in the execution...

Code:

int main(){    
    
	...
	MYSQL	*p_Connection; 
	...
	Initiate_mysql(&p_Connection);	
        ...
	
}

void Initiate_mysql(MYSQL** p_Connection){
	const char*	Host = "xxxx";
	const char*	User = "xxxx";
	const char*	Password = "xxxx";
	const char*	Database = "xxxx";
	
	mysql_init(*p_Connection);
	
	if (!mysql_real_connect(*p_Connection,Host,User,Password,Database,0,NULL,0)) {
		fprintf(stderr, "Failed to connect to s_Value_OUTbase: Error: &#37;s\n", mysql_error(*p_Connection));
	}
	
}

**matsp** · 03-06-2008

Judging from this, you should do:

Code:

	*p_Connection = mysql_init(NULL);

--
Mats

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