Small looping problem

Sorry if you have seen this code already, but I have fixed it to almost work perfectly. My issue this time, is that, when A character is entered exceeding 9 characters, my program does not proceed to the appropreate loop.

Example of error:

Code:

Enter words no longer than 9 characters
Enter your 1st word :Bill
Enter your 2nd word :thiswillbemorethannine
Enter your 3rd word :Enter your 4th word :

The character checking loop is as follows;

Code:

for (b=0; b<10; b++)
		{
			buff[a][b]=fgetc(stdin);
			if (buff[a][b]=='\n')
			{
				buff[a][b]='\0';
				break;
			}

			if (b>=10)
			{
				printf("You have entered a word more than 9 characters\n");
					while((buff[a][b] = fgetc(stdin))!='\n')
					{
						a=-1;
						goto A;
					}
			}

		}

Maybe I miss understand how loops work, but when 'b' gets increased to 9, the loop runs, then does it get increased to 10, and not follow through with the loop because b<10 is FALSE? Thats my logic of it, so since b = 10 now, it should do my ERROR loop.

I know for a fact the loop above doesn't remove all the information in the buffer, so I don't exactly know how to do that either. (I can't use fflush)


Here is my program;

Code:

#include <stdio.h>
#include <string.h>

char word[10][19];
char buff[10][19];
int a,b,c,d,e;

int main ()
{
printf("Enter words no longer than 9 characters\n");
A:for (a=0; a<10; a++)
{
	if (a==0)
		printf("Enter your 1st word:");
	else if (a==1)
		printf("Enter your 2nd word:");
	else if (a==2)
		printf("Enter your 3rd word:");
	else
		printf("Enter your %dth word:", a+1);

		for (b=0; b<10; b++)
		{
			buff[a][b]=fgetc(stdin);
			if (buff[a][b]=='\n')
			{
				buff[a][b]='\0';
				break;
			}

			if (b>=10)
			{
				printf("You have entered a word more than 9 characters\n");
					while((buff[a][b] = fgetc(stdin))!='\n')
					{
						a=-1;
						goto A;
					}
			}

		}
		for (b=0; buff[a][b]!='\0'; b++)
			if (buff[a][b] >='a' && buff[a][b]<='z')
				buff[a][b]=buff[a][b] - 'a' + 'A';
			else if (buff[a][b] >='A' && buff[a][b]<='Z')
				buff[a][b]=buff[a][b] - 'A' + 'a';
		b--;
		for(c=0; b>=0; b--, c++)
			word[a][c]=buff[a][b];
		for(b=0; buff[a][b]!='\0'; b++, c++)
			word[a][c]=buff[a][b];
		word[a][c]='\0';

}
printf("Your unsorted list of words\n");
for (e=0; e<10; e++)
	printf("%s \n",word[e]);





return 0;
}

Originally Posted by Iconate

Sorry if you have seen this code already, but I have fixed it to almost work perfectly. My issue this time, is that, when A character is entered exceeding 9 characters, my program does not proceed to the appropreate loop.

Example of error:

Code:

Enter words no longer than 9 characters
Enter your 1st word :Bill
Enter your 2nd word :thiswillbemorethannine
Enter your 3rd word :Enter your 4th word :

The character checking loop is as follows;

Code:

for (b=0; b<10; b++)
		{
			buff[a][b]=fgetc(stdin);
			if (buff[a][b]=='\n')
			{
				buff[a][b]='\0';
				break;
			}

			if (b>=10)  /*b is never >= 10, it quits the loop, after 9*/
			{
				printf("You have entered a word more than 9 characters\n");
					while((buff[a][b] = fgetc(stdin))!='\n')
					{
						a=-1;
						goto A;
					}
			}

		}

Maybe I miss understand how loops work, but when 'b' gets increased to 9, the loop runs, then does it get increased to 10, and not follow through with the loop because b<10 is FALSE? Thats my logic of it, so since b = 10 now, it should do my ERROR loop.

I know for a fact the loop above doesn't remove all the information in the buffer, so I don't exactly know how to do that either. (I can't use fflush)


[/code]

The variable b will loop from 0 to 9, not ten. Your if statement about b >= 10, is never reached as the program runs.