passing command line argument

[Tim]

Hi:

int main(int argc, char *argv[]) {
if (argv[1] == "go")
method(argc, ?????);
}

/**********************/
void method(int argc, char *argv[]){
/*stuff*/
}



What should go in ????
I am trying *argv[], **argv, argv[]
none of them is working!

[quzah]

> if (argv[1] == "go")

This won't work. Use 'strcmp', or write your own string comparison function.

Second, why don't you just pass the string over that you want processed, where 'x' is some number:

myfunc( argc[x] );

With the prototype:

myfun( char * )

Quzah.

[Tim]

For the first part, my bad!

but for the passing the array, I don't know how many arguments the user is going to enter, and I want to pass all of them.

How do you pass an unkown array to another function, like in the case above?

Thanks.

[quzah]

Just use the same way that 'main' uses it.

int main( int argc, char *argv[] )

Then call it the same way:

myfun( argc, argv );

Quzah.