Thread: Error in copying of charachters

are you using C99 mode?

use code tags for posting the code

you premier is uninitialized pointer pointing to some random location - you cannot write there.

allocate some buffer (staticaly or dynamically) before you write to the memory

vart means you never initialized premier. It is defined as a pointer, but does not point to anything.

Read up on malloc/free or use a buffer on the stack instead.

for example declare premier as
char premier[5];

to allocate 5 bytes in this buffer

Actually, I think vart was referring to this:

Code:

for (int v = 0; v < 5; v++)

Declaring variables in for loop initialization sections like that is C99 -- or C++. Try putting "int v;" somewhere near the beginning of a block -- say, the beginning of the enclosing function -- and then using just plain

Code:

for(v = 0; v < 5; v++)

Strangely, though, Dev-C++ usually lets you do that . . . .

Read up on malloc/free or use a buffer on the stack instead.

To elaborate: if you declare a pointer, it doesn't point to anything. You can't assign anything to the pointer, because you'll be writing into space that you are not allowed to write to. (In all likelihood.)

In order to get space to write to, you either need to use stack space and declare an array

Code:

char data[80];

or use heap space and dynamically allocate memory:

Code:

char *data = malloc(80);
/* ... */
free(data);

Static arrays do not need to be freed, but they are of a fixed size. Which you use depends on what you need.