converting string to int back to string

User will enter 2 strings from console ie 2342223423 and 23422

and I have to add them up as if they were integers.

I already have the code that will fill in the zeros like 2342223423 and 0000023422 so the addition can be done easily.

what I have been doing is I created a temporary int array that stores the values of the two strings being added by using the atoi method and seem to be having issues with it.

Also trying to use the itoa as well.

my method head is large_sum( char * num1, char *num2, char *answer)

where i have to return answer back to the main method to print it.

I have done this in java but used linked lists but I am forced to do C and use arrays.

any suggestions as to why I am having issues with the atoi then itoa ?

I just want to basically parse the string from the end to front, into ints, add them.. take that value and convert back into a char and put it into the answer array which is a string...

If I remember correctly, itoa() is non-standard.

You could just use atoi() to convert the two strings to int, add them, and then use sprintf() to convert the result to a string.

If you have any concern as to error handling of the input, I would recommend the more tolerant strtol() function for "string to integer".

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Mats

Quote:

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Originally Posted by laserlight

If I remember correctly, itoa() is non-standard.

You could just use atoi() to convert the two strings to int, add them, and then use sprintf() to convert the result to a string.

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Yeah but the reason for this method is to be able to take an infinite sized number and be able to add them.

so I you can add 23429834290189012387340129342134129083412342134012 98471239047123421304892734 + 2340298347129084719028421390412341232341123

and not worry about any over flows...

Oh, so you are writing a simple bignum calculator.

In this case atoi() and strtol() are unnecessary. Just note that given a char c that contains a digit, c - '0' returns the actual value of that digit. For example, if c = '5' then c - '0' = 5.