Doubt

This is a discussion on Doubt within the C Programming forums, part of the General Programming Boards category; Iam a lerner of c lanuage my question is that compiler take escape seqence /n /a /b etc here '\' ...

  1. #1
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    Doubt

    Iam a lerner of c lanuage
    my question is that
    compiler take escape seqence /n /a /b etc
    here '\' and 'a' are two chareters the the compiler
    take as one charecterwhy tell me reason behind it??????
    Last edited by sureshsuresh528; 02-01-2008 at 01:37 AM. Reason: to get clarify

  2. #2
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    compiler take escape seqence /n /a /b etc
    take as one charecterwhy tell me reason behind it?
    Because '\n', '\a', '\b' etc represent one character each.
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  3. #3
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    well compiler alsoconfuses the / with the \ soit misunderstands itasone character
    Last edited by manav; 02-01-2008 at 02:01 AM.

  4. #4
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    The reason those "escape codes" are uses is that there is no (easy) way to represent characters such as backspace, newline and bell-sound - they are traditionally "unprintable" - so to make them easily visible, the compiler allows the use of '\n' for newline, '\b' for backspace and '\a' for "bell" (or "alarm").

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