Filling up a 2D (or 3D) array.

How am I supposed to fill up a 2D array?
I've managed to get away with the following:

Code:

#include <stdio.h>

int main()
{
int board[3][3] = {0, 0, 0, 0, 0, 0, 0, 0, 0};
int a, b;
int i;
int j;
for (i = 0;i < 3; i++)
    {
     for (j = 0; j < 3; j++)
     {
      printf("&#37;d", board[i][j]);
     }
     printf("\n");
    }
printf("Input a: ");
scanf("%d", &a);
printf("Input b: ");
scanf("%d", &b);
board[a][b] = 1;

for (i = 0;i < 3; i++)
    {
     for (j = 0; j < 3; j++)
     {
      printf("%d", board[i][j]);
     }
     printf("\n");
    }

getchar();
getchar();
}

It works fine, but is it correct?



Thank You!

(I mean with pre-set numbers, I understand that you could fill it with zeros just by using a loop.)

you have a 3X3 int array, so you need 3 entries (rows), each 3 (columns) wide- for a total of 9 constants. You have the 9 constants, but not in row/column sets.

Code:

 
int board[3][3] = {0, 0, 0, 0, 0, 0, 0, 0, 0};

To init an int[3] array, you would code:

Code:

int board[3] = {0,0,0}  ;

To init an int [2][2] array, you would code:

Code:

int board[2][2] = { 
                  {0,0} , 
                  {0,0} 
                  }

Get it?

Todd