Why doesn't this poker C program work?

Code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void shuffle(int [][13]); //shuffle function prototype
void deal(int [][13], char *[], char *[]); //deal function prototype

void main()
{
		char *suit[4]={"Hearts", "Diamonds", "Clubs", "Spades"}; //suit pointer array
		char *face[13]={"Ace", "Deuce", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Jack", "Queen", "King"}; //face pointer array

		int deck[4][13] = {0};
		
		srand(time(0));
		
		shuffle(deck); //shuffle function call
		deal(deck, face, suit); //deal function call
}

void shuffle(int workdeck[][13]) //shuffle function
{
	int card, row, column;
	for(card = 1; card <= 52; card++)
	{
		row = rand() % 4;
		column = rand() % 13;
		while(workdeck[row][column] != 0)
		{
			row = rand() % 4;
			column = rand() % 13;
		}

		workdeck[row][column] = card;
	}
}

void deal(int workdeck2[][13], char *workface[], char *worksuit[])
{
	int card, row, column;
	int pairs = 0;
	int count = 0;
	
	for(card = 1; card <= 5; card++)
		for(row = 0; row <= 3; row++)
			for(column = 0; column <= 12; column++)
				if(workdeck2[row][column] == card)
				{ 
					printf("%5s of %-8s", workface[column], worksuit[row]); 
					if (card % 2 == 0)
						puts("");
					else
						printf("\t");
				}
	
	workface[column]++;
	worksuit[row]++;
	
	for(column = 0; column <= 12; column++)
	{
    	if(*workface[column] == 4)
    		printf("Four of a kind.");
    	if(*workface[column] == 3)
    		printf("Three of a kind.");
    	if(*workface[column] == 2)
    		pairs++;
		if(pairs == 1)
			printf("Pair.");
		if(pairs == 2)
			printf("Two pairs.");
	}
	
	column = 0;
	while(*workface[column] == 0) 
	{
		column++;
		for(; column <= 12 && *workface[column]; column++)
			count++;
		if(count == 5)
			printf("Straight.");	
	}
			 
	for(row = 0; row <= 3; row++) 
		if(*worksuit[row] == 5)
			printf("Flush");
}

I can get the program to deal out the cards, but I can't get it to determine the hand.

All this part of the deal function doesn't look correct

Code:

    	workface[column]++;
	worksuit[row]++;
	
	for(column = 0; column <= 12; column++)
	{
    	if(*workface[column] == 4)
    		printf("Four of a kind.");
    	if(*workface[column] == 3)
    		printf("Three of a kind.");
    	if(*workface[column] == 2)
    		pairs++;
		if(pairs == 1)
			printf("Pair.");
		if(pairs == 2)
			printf("Two pairs.");
	}
	
	column = 0;
	while(*workface[column] == 0) 
	{
		column++;
		for(; column <= 12 && *workface[column]; column++)
			count++;
		if(count == 5)
			printf("Straight.");	
	}
			 
	for(row = 0; row <= 3; row++) 
		if(*worksuit[row] == 5)
			printf("Flush");

Don't forget how you declared your deal function:

Code:

void deal(int workdeck2[][13], char *workface[], char *worksuit[]);

This means such things as:

Code:

workface[column]++;         // You are incrementing a (char *), which doesn't have sense in your case

Code:

if(*workface[column] == 4)  // You are checking if the first char of a string
                            // has the numerical value of 4, which is also non-sense

I'll let you think about it, because you do need to rethink about how you could do such things. Maybe someone could give you some hints, too. But I'm quite sure that you see at least why it's wrong.

You can simplify everything by representing a card as a single int,
and representing the deck as a single dimensional array of ints.

int card;
int deck[52];

Initially load the deck with the values 0 to 51.
Shuffling and dealing should be a lot easier.

To determine a card's suit and value:

suit = card / 13; /* number between 0 and 3 */
value = card % 13; /* number between 0 and 12, add 1 for 1 to 13 */

Do you have the final answer to this program?? I'm having some troubles trying to programing the same program.

> Do you have the final answer to this program?
Post your specific attempt in a new thread.