Thread: Decimal to hexadecimal conversion

I am trying to convert a decimal number (max. 255 / 8 bits) to hexadecimal and binary form. For now only tried to run the hexadecimal one, but somehow it keeps crashing without any information after running it. Can anyone spot the mistake?

// The result should in fact be put in a structure variable, and of course numbers > 9 should become letters. I can try that later, but if this doesn't work then any extra things won't either. Also not sure how to declare the variables properly, this is but one variant of the things I tried.

Thanks in advance!

Code:

#include <stdio.h>

struct hex1
{
unsigned result1;
unsigned result2;
};

int main ()

{
struct hex1;
int number;
unsigned result1;
unsigned result2;

printf("enter a number\n");
scanf("%d", & number);

result1 = number / 16;
result2 = number - (result1 * 16);

printf("result %d%d\n",result1,result2);

}

Well the thing is that you need to instruct the program to wait before closing. This is how you do it:

Code:

#include <stdio.h>

struct hex1
{
unsigned result1;
unsigned result2;
};

int main ()

{
struct hex1;
int number;
unsigned result1;
unsigned result2;

printf("enter a number\n");
scanf("&#37;d", &number);

result1 = number / 16;
result2 = number - (result1 * 16);

printf("result %d%d\n",result1,result2);
getchar();
getchar();

}

The getchar(); waits from a push on the enter key from the user; you could also run it in a dosbox.

Yup this works, thanks!

Now trying to convert them to letters, but you can't put those in integers so I made chars instead. However I think you need to use pointers for this (as it says invalid conversion when running it) and I am not sure how to do it.

I used the previous code and added for example:

Code:

if (result1 = 10)
    {
    charresult1="A";    
    }

if (result1 = 11)
    {
    charresult1="B";    
    }

if (result1 = 12)
    {
    charresult1="C";    
    }

if (result1 = 13)
    {
    charresult1="D";    
    }

if (result1 = 14)
    {
    charresult1="E";    
    }

if (result1 = 15)
    {
    charresult1="F";    
    }

How could I get this to work without an error?

Also, I'm guessing it is not possible to convert an integer directly to a char like this?

Code:

if (result1 < 10)
    {
    charresult1=result1;    
    }

In hexadecimal, numbers for 10 -> 16 are replaced by letters, which is what I am trying to achieve after using omnificient's corrected code and declaring charresult1 and charresult2 as char variables. But how/why using an array? And should I do something = 'something' instead? :/