isbn number.

This is a discussion on isbn number. within the C Programming forums, part of the General Programming Boards category; i need help with the error Code: #include <stdio.h> #include <stdlib.h> #define size 11 int check(int a[size]); int main() { ...

  1. #1
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    isbn number.

    i need help with the error

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #define size 11
    
    int check(int a[size]);
    
    int main()
    {
       char a[size],
            i,
            x;
    
       printf("Enter 10 character ISBN number (Do Not Separate ISBN Characters With"
              "Spaces): \n\n");
    
       for(i=0; i<=10; i++)
          a[i]=getchar();
    
       x=check();
    
       if(x==a[9])
          printf("ISBN is valid.");
       else
          printf("ISBN is invalid");
    
    
       system("PAUSE");
       return 0;
    }
    
    int check()
    {
       int sum,
           x,
           y=0;
    
       for(i=0; i<=9; i++)
          a[i]=a[i]-48;
       for(i=0; i<=9; i++)
       {
          x=y+(i+1)*a[i];
          y=x;
       }
       sum=x%11;
       return sum;
    }

  2. #2
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    222
    what errors are you getting? More details would be nice.

  3. #3
    Registered User NeonBlack's Avatar
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    435
    look at the prototype for check.

  4. #4
    C++まいる!Cをこわせ! Elysia's Avatar
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    22,548
    Quote Originally Posted by xxbleh View Post
    i need help with the error

    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #define size 11
    
    int check(int a[size]);
    
    int main()
    {
       char a[size],
            i,
            x;
    
       printf("Enter 10 character ISBN number (Do Not Separate ISBN Characters With"
              "Spaces): \n\n");
    
       for(i=0; i<=10; i++)
          a[i]=getchar();
    
       x=check();
    
       if(x==a[9])
          printf("ISBN is valid.");
       else
          printf("ISBN is invalid");
    
    
       system("PAUSE");
       return 0;
    }
    
    int check()
    {
       int sum,
           x,
           y=0;
    
       for(i=0; i<=9; i++)
          a[i]=a[i]-48;
       for(i=0; i<=9; i++)
       {
          x=y+(i+1)*a[i];
          y=x;
       }
       sum=x%11;
       return sum;
    }
    Inconsistent (or wrong) parts of the app is colored red.

  5. #5
    and the hat of wrongness Salem's Avatar
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    > if(x==a[9])
    x will be an integer 0 to 9
    a[9] will be a char '0' to '9'
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
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