Thread: Dynamic Array

In this part of my program i -obviously- want to create a dynamic array.
But somewhere there is a problem(the array is allocacated but not returned), can anyone help me, is there any problem with the pointers?
I have a warning into the main that A hasn't been initialized

Code:

#include<stdio.h>
#include<time.h>
#include<stdlib.h>

int FillStruct(int A[]);

int main(void){
	
	int megethos,*A,epilogi;
	srand(time(NULL));
	
	do{
		printf("--------------------------\n       Main Menu\n--------------------------\n");
		printf("Give a choice: ");
		scanf("%d",&epilogi);
		switch (epilogi) {
		case 1:
			megethos=FillStruct(A);
			break;
	.
	.
	.
	.
	.
        }
	return 0;
}

int FillStruct(int A[])
{
	int type,zevgaria,thesi,temp,i,megethos;
	printf("Please give the length of the struct:");
	scanf("%d",&megethos);

	A=(int*)calloc(megethos,sizeof(int));
	if (A==NULL){
		printf("ALLOCATING MEMMORY ERROR");
		exit(1);
	}
	return megethos;
}

Thanks, you are right! And if i want to refer to the array in that function, i have to write *A[]??
For example why something like that is wrong??

Code:

int FillStruct(int **A)
{
	int type,zevgaria,thesi,temp,i,megethos;
	printf("Please give the length of the struct:");
	scanf("%d",&megethos);

	*A = calloc(megethos,sizeof(**A));
	if (*A==NULL){
		printf("ALLOCATING MEMMORY ERROR");
		exit(1);
	}
        for(i=0;i<megethos;i++) *A[i]=i ;
	return megethos;
}

I don't have any errors but it can't be executed either