Return pointer to 2d array
hi all,
i want to creat a 2D array and return the pointer of it, and then pass the
pointer to another function. How can i write my "return" code and define
the second function's "parameter" type?
thanks.
Code:#include <stdio.h> int creat2dArray() { int array[10][10]= {0}; return (int**)array; } void 2dpointers(int *p[10]) { ; } int main(void) { 2dpointers(creat2dArray()); return 0; }
array in create2dArray() will be destroyed when the funcion exits.
Use malloc() to create the array on the heap.
Last edited by zacs7; 10-22-2007 at 04:34 AM. Reason: Spelling :)
The syntax ain't pretty...
If you mean to return a real array, you need to make it static to prevent it going out of scope when the function returns.Code:#include <stdio.h> int (*creat2dArray())[10] { static int array[10][10]= {0}; return array; } void twodpointers(int (*p)[10]) { ; } int main(void) { twodpointers(creat2dArray()); return 0; }
As zacs7 says, you should use malloc for a far more flexible solution.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
got it! many thanks!
