No print

Dose anyone know why this program will not print for me?

Thanks

Code:

#include <stdio.h>
#include <ctype.h>
int main(void)
{
   char c;
   int low_ct = 0;
   int up_ct = 0;
   int punc_ct = 0;
   int dig_ct = 0;
   int n_words = 0;
   bool inword = false;

   printf("Enter text to be analyzed (EOF to terminate):\n");
   while ((c = getchar()) != EOF)
   {
        if (islower(c))
           low_ct++;
        else if (isupper(c))
           up_ct++;
        else if (isdigit(c))
           dig_ct++;
        else if (ispunct(c))
           punc_ct++;
      if (!isspace(c) && !inword)
      {
         inword = true;
         n_words++;
      }
      if (isspace(c) && inword)
         inword = false;
   }
   printf("\nwords = %d, lowercase = %d, uppercase = %d, "
          "digits = %d, punctuation = %d\n",
           n_words,low_ct,up_ct, dig_ct, punc_ct);
           

   return 0;
}

Did you enter "EOF"? That's usually Ctrl-Z or Ctrl-D.

gg

Originally Posted by Codeplug

Did you enter "EOF"? That's usually Ctrl-Z or Ctrl-D.

gg

Thanks

Sorry stupid Question forgot to do that problem solved.

You'll also want to make your c variable an int, not a char. It seems a bit counterintuitive, but since getchar() must be able to return all possible char values plus a signal on end-of-file, a larger type has to be used (for nitpickers, yes, int and char can be the same size, but generally that's not relevant).

Using char can cause EOF to be signalled early; on a lot of implementations the ÿ character (that's a y-diaeresis if it doesn't come through) will look like EOF. Or it's possible for EOF never to be signalled!