A lil confused

This is a discussion on A lil confused within the C Programming forums, part of the General Programming Boards category; Need to know how the following code would function... Code: #include<stdio.h> int main() { int i=7; printf("%d",i++*i++); } for the ...

  1. #1
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    A lil confused

    Need to know how the following code would function...

    Code:
    #include<stdio.h>
    int main()
    {
    int i=7;
    printf("%d",i++*i++);
    }
    for the above mentioned the output is 56
    if i were to change it to
    Code:
    printf("%d",i++*i)
    still the same output
    Code:
    printf("%d",++i*i++)
    outputs it as 64

    Cant figure out how its going about executing the statement, would appreciate help on this.

  2. #2
    and the hat of wrongness Salem's Avatar
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    http://c-faq.com/expr/index.html
    It's undefined.

    In short, if you modify the same variable twice, or modify and read the variable, then all bets are OFF as to what actually happens.

    Follow that link to further read up on something called "Sequence Points".
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
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