Thread: Help Please!

if anyone can please help i have to turn in this program by 2moro night and ive been up all night trying to figure it out. i had to write a program to find all the factors of any given number typed as long as it is a possitive interger. then i have to 1. list the possitive intergers. 2. show how many intergers there are. 3 add all the intergers and 4 multiply them. i will paste what i have so far but i am having trouble with showing 2-4! please just give me advice or anything. thanx

Code:

#include <stdio.h>

int main () {
    int val, factor, sum;
    int product, total;
    printf("Enter a positive integer greater than one: \n");
    scanf("&#37;d", &val);
    
    factor=1;
    
    if(val<0){
              printf("Sorry, that input is not valid. \n""Enter a positive integer greater than one.");
              }
              else{
    
    printf("Here is a list of the possitive intregers of %d\n", val);
    while(factor<=val){
    
             if(val%factor==0){
            
             printf("%d ", factor);    
                              
                              }//if end
    factor=factor+1;
    }//while end

//sum               
    sum=1;
    while(sum<=val);{
                      if(val%sum==0){                                  
                                     }                 
total= sum+sum;



}//while end
printf("%d\n",total);
}//else end
    printf("\n");
    
    
    system("pause");
    return 0;
}

yeah i know. this is my second program ever so i guess i can use that as an exuse. i got the program to add and multiply but i stayed up unitl 4 trying to figure out how to get it to count. i was going to organize it when i finished though, and play with it so i could have only one while loop. i just wanted it to do what i asked first no matter how sloppy it was. thanx for the help though!

Originally Posted by lilcoder

you're code arrengement looked horrible to me... Take a look at this: http://irc.essex.ac.uk/www.iota-six...._operators.asp

Code:

#include <stdio.h>

int main (void) {

    int val, factor=1,count=0,sum=0,multip=1;

    printf("Enter a positive integer greater than one: \n");
    scanf("%i", &val);
    
    if(val<0){
              printf("Sorry, that input is not valid. \n""Enter a positive integer greater than one.\n");
              return 0;
                   }
              
    
   printf("\nHere is a list of the possitive integers for %i:\n", val);
 
   while(factor<=val){
                    if(val%factor==0){
                          printf("%i\n", factor);    
                          count++;         /*counts how many integers we found*/
                          sum+=factor;  /*sums them*/
                          multip*=factor; /*multiplies them*/
                                                  }
                    factor++;
                                    }

    printf("We have a total of %i integeres.\nWhich are summed together: %i and multiplied:%i\n",count,sum,multip);
    
    return 0;
}

I suppose that if i have completely understand what you want to do, your strategy is wrong.
Consider a number like 8, first factor is 2, you have 8 / 2 = 4, for the next factor you set the factor to factor++ so you have the number 3 to get divided with the number 4. Thats error as the next number that factor is is still the number 2.
8 = 2 * 2 * 2;
Also should you consider creating a function to tell if is a prime number or not, if the given number is prime then say it is prime and print it.
Think of it.