4 char's from one int. . .

This is a discussion on 4 char's from one int. . . within the C Programming forums, part of the General Programming Boards category; Say I have an unsigned int x = 0x4F726E67, and I want to print the character values of that int( ...

  1. #1
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    4 char's from one int. . .

    Say I have an unsigned int x = 0x4F726E67, and I want to print the character values of that int( 0x4F, 0x72, 0x6E, 0x67 ) becomes ( 'O', 'r', 'n', 'g' ) either to stdout or to a file. There must be an easy way of doing this but it has eluded me. Any hints would be appreciated.

    Example of an attempt using strtol:
    Code:
    	for( i=0; i<length/4; i++ ) {
    		fread( &c, 4, 1, in );
    		
    	       	c = c ^ 0x54694772;
    		printf("c = &#37;d = 0x%x\n", c, c );
    		unsigned int foo = strtol( c, NULL, 2 );
    	fwrite( &foo, 1, 1, out );
    	}
    		
    	
    	fclose( in );	// Closes input file
    	fclose( out );	// Closes output file
    	return 0;
    }
    Last edited by k2712; 09-16-2007 at 12:10 PM.

  2. #2
    Just Lurking Dave_Sinkula's Avatar
    Join Date
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    Posts
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    One possible method:
    Code:
    #include <stdio.h>
    #include <limits.h>
    
    int main(void)
    {
       unsigned int value = 0x4F726E67;
       size_t i = sizeof value - 1;
       do {
          putchar(value >> CHAR_BIT * i);
       } while ( i-- > 0);
       return 0;
    }
    
    /* my output
    Orng
    */
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

  3. #3
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    Thank you Dave, that works perfectly.

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