Thread: Problem accepting a character

Hi,

My environment is Visual C++ 6.0. On executing the below code, its not waiting for me to enter a character. After I enter a number, it goes directly to the printf statements. Please help...

Code:

#include <stdio.h>

int main(int argc, char** argv)
{
	char c;
	int d;
	printf("Enter a no:\n");
	scanf("%d",&d);
	printf("Enter a character\n");
	scanf("%c",&c);
	printf("The number you entered is %d",d);
	printf("The character you entered is %c",c);
        return 0;
}

Try this:

Code:

#include <stdio.h>

int main(int argc, char** argv)
{
	char c;
	int d;
	printf("Enter a no:\n");
	scanf("%d",&d);
	printf("Enter a character\n");
	getchar();
    scanf("%c",&c);
	printf("The number you entered is %d",d);
	printf("The character you entered is %c",c);
    getchar();
    return 0;
}

I stuck a couple of getchars in it. Basically your first scanf takes a number but leaves the '\n' character from when you hit enter in the input buffer. The second scanf looks at the input buffer, sees the '\n' and takes it. The getchar basically just flushes it.

Code:

#include <stdio.h>

int main(int argc, char** argv)
{
	char c;
	int d;
	printf("Enter a no:\n");
	scanf("&#37;d",&d);
	printf("Enter a character\n");
                fflush(stdin);
                scanf("%c",&c);
	printf("The number you entered is %d",d);
	printf("The character you entered is %c",c);
        return 0;
}

use fflush(stdin);
before scanf("%c",&c)
ur problem will be solved

hey can u tell me why fflush is wrong??
still it clears your problem??