strcat problem

Code:

---

for(int i =0; i<boardCount; i++)
{
        char boardName[] = "dxxxB";
                strcat(boardName,i);
}

---

how can I add the integer to the end of string and let compiler interpret it as a whole big char array? Pls help me and thank you in advance

check sprintf(...);

Even if I look sprintf it seem like only formating strings and do not return them I have to return DXXXB1, DXXXB2 and pass them to a function as reference, could you help me?

Also getting errors cannot convert int to constant char, is there anything else such as append string? I am very unfamiliar with C thank u in advance

is this something that you need?

Code:

---

#include<stdio.h>
#include<stdlib.h>


char *func()
{
        char *array=calloc(100,sizeof(char));
        int i;

        i=1;
        sprintf(array,"DXXXB&#37;d",i);

        return array;
}



int main()
{
        char *p;

        p=func();
        puts(p);
        free(p);

        return 0;
}

---

You can't pass by reference in C, however you can pass a pointer.

you'll have to resize boardName (it's allocated on the stack), since it's not large enough to hold anymore than "dxxxB"+1 characters, either make it big enough, or use dynamic memory allocation.

such as:

Code:

---

#include <stdio.h>

void foo(char * s);

int main(void)
{
    char boardName[32];
    size_t i;

    for(i = 0; i < boardCount; i++)
    {
        sprintf(boardName, "dxxxB&#37;d", i);
        foo(boardName);
    }

    return 0;
}

void foo(char * s)
{
    /* do whatever with s */
    return;
}

---

Thanx you. Both of them work and I learnt more than I expect.