Thread: if statement reads char value as variable

This is my second time using the char variable so please forgive the silly question. How do I make this work? It's towards the bottom.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
   int inLoop = 0, outLoop = 0, input;
   int numberOne, numberTwo;
   char inputChar;

   while (outLoop == 0) {
      srand( time(NULL) );

      while (inLoop == 0) {
         numberOne = rand();
         numberTwo = rand();

         printf("What is %d times %d? ", numberOne, numberTwo);
         scanf("%d", &input);

         if (input == (numberOne * numberTwo) ) {
            printf("Correct!\n");
            inLoop = 1;
         }
         else
            printf("Wrong, try again\n");
      }

// --------------------------This is where the problem is occuring -------------------------------------------
   while (inputChar != y && inputChar != Y && inputChar != n && inputChar != N) {
      printf("Would you like to do another one(y or n)? ");
      scanf("%c", &inputChar);

      if (inputChar == y || inputChar == Y)
         continue;
      else if(inputChar == n || inputChar == N)
         inLoop = 1;
      else
         printf("You can only enter y or n\n");
   }

   return 0;
}

I think y, Y, n, and N need to be in single quotes (i.e., 'y', 'Y', etc.).