Thread: Program won't calculate mean or sleep

Originally Posted by MacGyver

Print it as a double, not an int. Use either %f or %lf. I can't remember which printf() takes, but it's definitely not %i or %d for doubles.

Also, why not just call sleep() or Sleep() yourself? For Windows include <Windows.h>, and call Sleep() with the number of milliseconds to sleep, which in your case would be 3000.

printf and scanf both use f for float and lf for double.

That <Windows.h> still doesn't fix the problem it gives the same result as system("Sleep 3s").
The final printf is still not showing.

The sum of num1 + num2 + num3 is 0 for some reason.

Originally Posted by Deerman

That <Windows.h> still doesn't fix the problem it gives the same result as system("Sleep 3s").
The final printf is still not showing.

Because you didn't put "\n" at the end of the string.

printf("The mean of the three numbers you entered is&#37;i", mean);

You're using %i, it should be %lf. McGyver told you the same earlier.

By the way, this isn't standard C, you aren't declaring your variable at the good place (you are doing like those silly C++ programmers who are declaring variables everywhere ). C let you only declare variables after an '{' or after another variable declaration (in the case it's not global variable).

That said... you could change this

Code:

 mean = (double) num1 + (double) num2 + (double) num3;
 mean /= 3.0;

for this

Code:

mean = (double) (num1 + num2 + num3);
mean = mean / 3.0;

or, simple, this

Code:

mean = (num1 + num2 + num3) / 3.0;

or

Code:

mean = (double) (num1 + num2 + num3) / 3;

Anyway, just to point out that there is "better" way to use cast than others.

Your mean variable should first be initialized to double standard 0.00, and

mean = (num1 + num2 + num3) / 3.0; should give you the ideal result with a printf("&#37;lf", mean) or %.2lf for precise 2 decimals.