A question regarding strings

This is a discussion on A question regarding strings within the C Programming forums, part of the General Programming Boards category; Hi, I've a doubt working with strings. To store a name into a character array, I give like Code: char ...

  1. #1
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    Question A question regarding strings

    Hi,

    I've a doubt working with strings. To store a name into a character array, I give like
    Code:
    char Temp[]="Array";
    . Here the declaration and the initialization of the array is done in a single step. But what if I want to initialize the array later in my program. Is there any way to do it?

    Thanks,
    Babu

  2. #2
    Woof, woof! zacs7's Avatar
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    Since Temp is on the stack you'd still have to specify it's size, then you can copy data into it later.

    eg:
    Code:
    char Temp[32];
    
    /* ... */
    strcpy(Temp, "Hello World");
    /* Temp now holds "Hello World" */
    Basically the compiler fills in the empty brackets when you do: char Temp[]="Array";, it See's that 'Temp' only has to be 6 bytes long (Array + NUL)

  3. #3
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    Code:
    char Temp[]="Array";
    is semantically

    Code:
    char const Temp[]="Array";
    What exists in memory is "Array" and 'Temp' is just an alias, NOT a variable per se...

    I would LOVE to stand corrected.

  4. #4
    Deathray Engineer MacGyver's Avatar
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    Well, Temp is an actual array in this case, and "Array" is copied to it automatically (hence why on systems where string literals are read-only, you can alter these arrays).

    Code:
    char *Temp = "Array";
    Code:
    char Temp[] = "Array";
    Two totally different meanings. One points to the string literal (generally in read-only memory), and one is an actual array that has the string copied to it upon creation.

  5. #5
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    The first is a pointer variable which on initialization points to the location where "Array" is stored, but can be reassigned to any time....

    The second is an array in which "Array" is stored. We MIGHT overwrite that location, but the compiler will definitely not allow us to do that directly.

    Am I making sense or am I just plain wrong man?

  6. #6
    and the hat of wrongness Salem's Avatar
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    You're just plain wrong.
    But perhaps you should start your own thread rather than hijacking someone elses from several weeks ago.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
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  7. #7
    Registered User ssharish2005's Avatar
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    The second is an array in which "Array" is stored. We MIGHT overwrite that location, but the compiler will definitely not allow us to do that directly.
    Compiler will allows us to overwrite it unless yoy declare it as an const variable. Have a look at this code

    Code:
    #include <stdio.h>
    
    int main()
    {
        char temp[] = "string"; 
        
        /* You should be more careful here since it is temp3[6] */
        strcpy(temp,"Test");
        
        printf("&#37;s",temp);
        
        getchar();
        return 0;
    }
    
    /* my output
    Test
    */
    ssharish2005

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