Thread: Declaring pointer to variable in struct

Hello. If I have the following struct

Code:

struct rec {
       char name[20];
       int age;
}p1;

struct rec *ptr = &p1;

strcpy(ptr->name, "John");
ptr->age = 20;

How do I declare a pointer to "name" within the structure so that I could
use it to move through the name array for whatever reason? I know
that "ptr->name" is a pointer to name, but can I increment this pointer to access
individual bytes within name[]?

Sorry, I'm kinda new to structures.
thanks

Code:

ptr->name[0]

for the first char.

or

Code:

char * chp = ptr->name;
*(++chp) = 'a'; /* to set the second char to 'a' */

Kurt

Code:

char *p = ptr->name;

Walk.

Safer way is probably to use ptr->name as the array that it is and index it with a counter variable.

Edit: Slow again.

You can index the pointer, or use another pointer:

Code:

for ( i = 0; ptr->name[i] != '\0'; i++ )
  printf ( "%c\n", ptr->name[i] );

for ( p = ptr->name; *p != '\0'; p++ )
  printf ( "%c\n", *p );

name is an array, so you can't use it as a pointer to iterate over the contents of the array.

Like
char *cp = &p1.name;

> Edit: Slow again.
Call me Mr Glacier

Thanks everyone!