Thread: Word Counting

Look at the whole block of code:

Code:

if(c == ' ' || c == '\n' || c == '\t')
            state = OUT;
        else if (state == OUT) {
            state = IN;
            ++nw;
        }

Now imagine that you're scanning thru some text, and you are IN side a word. Now you come to a blank space or a newline, or a tab.

That would switch you to being OUT side a word. Now if you are OUT side a word, and you came to a char, and that char was NOT a blank space OR a newline, OR a tab, then the program goes to that else if, and finds out "if I have reached a new char, and that new char is not any of those three mentioned choices above, then it MUST be a char to start a new word. Therefore, I'm back IN side a word again. So increment the new word variable by one.

I understood the whole program and I want to thank anybody! I also decided to challenge myself by writing a program that counts words only on myself! I know how to make it cound lines, tabs, backslashes, etc!BTW, how do I make a backspace?? I have the sequence \b put in the right spot! But what is a backspace in a C program! I pressed the backspace button but still, nothing!

Here is the code for the WORD COUNTING program, not the one with backspace problems!

Code:

#include <stdio.h>

#define OUT 0
#define IN  1

int main()
{
	int x, state, nw;
	
	state = OUT;
	nw = 0;
	while((x = getchar()) != EOF)
	{
	    if (x == ' '|| x == '\n'|| x == '\t')
	    	state = OUT;
	    
	    else if (state == OUT)
		{
			state = IN;
			++nw;
		}
	}
	printf("You have %d words\n", nw);
}

If you have time, pls consider giving me some critics and commentarries on it and help me improve it!

Thanks agin, To Everybody

I did want to take some courses but I thought again and I think it is more rewardable(at least for me) to learn C on my own! I am not doing it for money, just pure pleasure and satisfaction!

And one more thing I am going to bother you people with is that I want to make a program that will read input and return output one word per line!

I thought I could do printf("%d\n\n", word)but that would only leave 2 lines! Give me an idea!I really don't know !


Thanks!

I am trying to print one word per line from input!

So I suck at c would be:

I
Suck
At
C


That is what I am trying to do!

I know I am very very annoying but I just started learning C! The book gives this exercise in a section of word counting! As far as I got with this book, it never said one thing about ctype.h or isspace() or any functions like those! I just know how to count lines, words, spaces, tabs, copy input to output, and very simple stuff! What I am trying to say is that there has to be a more simple way to do this program! They wouldn't be stupid to give this exercise in the book when it hasn't covered this stuff yet!

So please can you tell me a simpler way of doing this program, even if it is longer! Just a very noob way to take input with getchar() or scanf() and print the output one word on a line!

Thanks!

One thing to keep in mind with programming in C - there's always more than one way to get the job done. Frequently, there are several ways.

You have just worked on a program to count words, and you know it works, right?

So I'm thinking of a simple program like this:

Code:

char input[80] = '\0';   /* this is NULL in char talk */

while (input != 'q')   {
   puts(" Enter some words, please: ");
   fgets(stdin, 79, input)
   
   printf(" %s \n ", input);

/* NOW, right here, you know what the string input is, and you know it has been entered OK,

Now we'll add some logic from your word counting code here, but change it a bit. Instead of *counting* the 
words, you want it to print just that one word, and then also print out a newline char '\n', 
when the end of the word is reached.
   printf("\n\n");
   length = strlen(input);
   for (i = 0, i < length; i++)  {
      if (input[i] != ' ' && input != '\n')
         printf("%c", input[i]);
      else
         printf("'\n'");
   }
}

Hope that helps. Don't get too frustrated because the initial learning cure is steep. Just go with it, and try not to get frustrated. C is not the easiest language around. It was written by
brilliant workers at Bell Labs, which was one of our better research labs, and it was based on
the work of still other brilliant researchers, who had invented langauges like 'B', before them.


As such, C was designed for professional programmers, with no intent to make it super duper easy for beginners. *POWERFUL* (efficient), was the name of the game.

Don't worry if the syntax for the code above won't compile, either. That's just a suggestion,
off the cuff. Play with it, see what does and does not work with it, and make improvements
and changes to it, as you see fit. Experimenting is important.


If you get stuck, just post up your problem.

I also tried to understand it! But since I am a very beggining person, I could not understand much of it! One day passed, I wrote no code! I felt like I forgot anything I learned up to that point so I decided to write a program that includes all the others I've done! But the program doesn't work!

The problem with this is that it keeps telling me I have 1 word even if I write whole pages! One word if I type anything, 0 words if I type nothing!

As you see, I have an integer called characters! That was supposed to count the characters in my text! I forgot that also!

Here is the code, it is driving me crazy and it is on my nerves since I can't figure out the problem why it tells me I have 1 word when I have many!

I would also appreciate some help on character counting

I also posted this on another thread, my mistake as it is 3:23AM when I am writing this!

Code:

#include <stdio.h>

#define OUT 0
#define IN  1

int main()
{
	while(1)
	{
		int x, state, words, lines, tabs, characters, blanks;
		state = OUT;
		words = lines = tabs = characters = blanks = 0;
	
		while((x = getchar()) != EOF)
		{
			if (x == '\n')
				++lines;
			else if (x =='\t')
				++tabs;
			else if (x == ' ')
				++blanks;
			else if (x == ' '|| x == '\n'|| x == '\t')
				state = OUT;
			else if (state == OUT)
			{
				state = IN;
				++words;
			}
		}
		printf("You have %d words:\n", words);
		printf("You have %d lines:\n", lines);
		printf("You have %d tabs :\n", tabs);
		printf("You have %d blanks:\n", blanks);
	}
}