# Segment woes

This is a discussion on Segment woes within the C Programming forums, part of the General Programming Boards category; Code: //TJ Wright 11 3 #include <stdio.h> int main () { int m, count=0,n[30]; printf("Enter the numbers, one per line"); ...

1. ## Segment woes

Code:
```//TJ Wright 11 3
#include <stdio.h>
int main ()
{
int m, count=0,n[30];

printf("Enter the numbers, one per line");

for(m=1;m<=20;m++)
{
scanf("%d",&n[m]);/* input up to 20 integers, one per line, the sentinel is 0
each of the numbers will be less than 2^30.*/
count++;
if(n[m]==0)break;
}

for (m=1;m<=count;m++)
{
/*

if statements asking if there is a number n such that all the integers
are in the segment [n, n+32767]. If there is such a number, print the largest
such n. If there is not, determine if there is a number n such that
all but  1 of the integers is in the segment [n,n+32767]. If there is such
a number, print the largest such. If there is no such, determine if there is
such an n so that all but two of the intervals are in the interval and print
the largest such. Continue this way until n is found.*/
}

return 0;
}```

2. arrays are zero based (indexes start at 0 not 1)
for 20 numbers you need array of 20 elements, not 30