terminating a while loop with a character

This is a discussion on terminating a while loop with a character within the C Programming forums, part of the General Programming Boards category; Hi, I'm trying to write a simple spell-check program where the user enters one word at a time, but I'm ...

  1. #1
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    terminating a while loop with a character

    Hi, I'm trying to write a simple spell-check program where the user enters one word at a time, but I'm having trouble terminating the program when the user is finished. I would like the program to finish accepting input when they user enters a period. This is what I've got, any help would be appreciated.

    Code:
    #include<stdio.h>
    #include<string.h>
    
    #define SIZE 46000
    #define WORD_SIZE 128
    
    int main( void )
    {
    	
    	// Reads linux.words into buffer array
    	FILE *dict;
    	dict = fopen( "linux.words", "r" );
    	if( ! dict )
    	{
    		printf( "Failed to input linux.words\n" );
                    return 1;
            }
    	char buffer[SIZE][WORD_SIZE];
            int i = 0;
            while ( fgets( buffer[i] , SIZE, dict ) != NULL ) {
                    i++;
            }
    	
    	char word[99][29];
    	int j;
    	
    	// This for loop reads one word at a time from the user
    	// and stores the words in an array to be encoded later.
    	
    	for( j=0; j<100; j++ )
    	{
    		printf( "Enter a word( . to quit )\n" );
    		fgets( word[j], 31, stdin );
    			if( (strcmp( word[j], "." )) == 1 )
    				j=100;
    		}
    		
    		
    	return 0;
    }
    With this the program only takes one word and then quits.

    Thanks.

  2. #2
    Registered User whiteflags's Avatar
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    Yes well
    Code:
    if( (strcmp( word[j], "." )) == 1 )
       j=100;
    It likely has to do with this. It would be rare for word[j] to contain a string that is just a period. That is the array &#123; '.', '\0' &#125; and not just the character '.' like you were thinking. Something like strchr would serve your purposes better.

    And while you're at it, learn how strcmp works. 1 is not a match.

  3. #3
    Lean Mean Coding Machine KONI's Avatar
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    Spell checker ... wow, that brings back a lot of memories. From using simple arrays to tries and the all powerful graph model to store a dictionary to finally dynamic programming and levenshtein distance to find the correct word.

    This could become interesting.

  4. #4
    and the hat of wrongness Salem's Avatar
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    > for( j=0; j<100; j++ )
    This overflows the number of words, by one word.

    > fgets( word[j], 31, stdin );
    This overflows the length of a word by a couple of characters.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

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