Help with passing multidimensional array to function by ref.

[PatrickSteiger]

Hey

Here is code one:

int main() {
	int i, j;
	int **matriz;
	// alocando espaço para as colunas
	matriz = (int **)malloc(N*sizeof(int *));
	// alocando espaço para as linhas, uma de cada vez
	for (i=0;i<N;i++)
		matriz[i] = (int *)malloc(N*sizeof(int ));
	// inserindo n&#250;meros na matriz
	for (j=0;j<N;j++)
		for (i=0;i<N;i++)
	      matriz[i][j] = 0;
}

Now what i am trying to do is this:

void criaMatriz(int** *matriz, int N);

void criaMatriz(int** *matriz, int N) {
	int i, j;
	// alocando espaço para as colunas
	*matriz = (int **) malloc(N*sizeof(int *));
	// alocando espaço para as linhas, uma de cada vez
	for (i=0;i<N;i++)
		*(matriz[i]) = (int *) malloc(N*sizeof(int));
	// inserindo n&#250;meros na matriz
	for (j=0;j<N;j++)
		for (i=0;i<N;i++)
	      matriz[i][j] = 0;
}
int main {
           ...
           criaMatriz(&matriz, N);
}

But i'm getting segfaults. Clearly i'm passing it (&matriz) the wrong way, or i'm making mistakes inside the function. the error occurs in the line

*(matriz[i]) = (int *) malloc(N*sizeof(int));

Any help is appreciated

[Salem]

> *(matriz[i]) = (int *) malloc(N*sizeof(int));
1. Don't cast malloc in a C program, see the FAQ.

2. You have to be really careful with the dereferencing and precedence here.
This should be
(*matriz)[i] = malloc(N*sizeof(int));

Likewise, later on
(*matriz)[i][j] = 0;

The initial call is fine.

[PatrickSteiger]

Uh.. dull sintax errors

I will take more attention next time

Thank you very much!