how can i truncate this

This is a discussion on how can i truncate this within the C Programming forums, part of the General Programming Boards category; hi all i have an output like this Code: ID=123:one=a:two=a@yahoo.com:three=789:four=:five=123 ID=123:one=aa:two=aa@yahoo.com:three=:four=1111111111:five= :/ i would like to truncate this write in ...

  1. #1
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    how can i truncate this

    hi all
    i have an output like this
    Code:
    ID=123:one=a:two=a@yahoo.com:three=789:four=:five=123 ID=123:one=aa:two=aa@yahoo.com:three=:four=1111111111:five=
    :/
    i would like to truncate this write in a file (file.txt) as
    Code:
    //begin
    a
    a@yahoo.com
    789
    
    123
    //begin
    aa
    aa@yahoo.com
    
    11111111
    
    //begin
    how can do this

    can you please help em
    thank you in advance

  2. #2
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    Quote Originally Posted by munna_dude View Post
    hi all
    i have an output like this
    Code:
    ID=123:one=a:two=a@yahoo.com:three=789:four=:five=123 ID=123:one=aa:two=aa@yahoo.com:three=:four=1111111111:five=
    :/
    i would like to truncate this write in a file (file.txt) as
    Code:
    //begin
    a
    a@yahoo.com
    789
    
    123
    //begin
    aa
    aa@yahoo.com
    
    11111111
    
    //begin
    how can do this

    can you please help em
    thank you in advance
    You could put this string into a char array and then scan through each char. The equal sign precedes the info you want written out to a file. So when the letter you're looking at is an equal sign, you know that you need to write out the next several char's, until you reach the colon, which marks the end of the field.

    What part are you stuck on? Show me your code to handle this, and explain your specific troubles, please.

    Adak

  3. #3
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    thank you for quick replay

    Quote Originally Posted by Adak View Post
    You could put this string into a char array and then scan through each char. The equal sign precedes the info you want written out to a file. So when the letter you're looking at is an equal sign, you know that you need to write out the next several char's, until you reach the colon, which marks the end of the field.

    What part are you stuck on? Show me your code to handle this, and explain your specific troubles, please.

    Adak
    Code:
    #include <netdb.h>
    #include <stdio.h>
    #include <stdlib.h>
    #include <linux/sockios.h>
    #include <string.h>
    #include <math.h>
    #include <dirent.h>
    
    #include <sys/types.h>
    #include <sys/stat.h>
    #include <fcntl.h>
    #include <errno.h>
    #include <unistd.h>
    #include <syslog.h>
    #include <stdio.h>
    
    void write_data();
    
    
    void write_data()
    {
    
    char *response="ID=123:one=a:two=a@yahoo.com:three=:four=456:five=\nID=123:one=aa:two=aa@yahoo.com:three=22222222:four=:five=0000000000\n:/";
    
                
            FILE *appenddatabase;
            char appendfile[256];
         
     
    char tempfile[256] = "/root/Desktop/1234/MyFriends.txt";
    
            appenddatabase = fopen(tempfile, "r");
             	if (appenddatabase == NULL)
            appenddatabase = fopen(tempfile, "w");               
    
          
                char *delims="\n";
                char *result = NULL;
                result = strtok(response,"\n");
                printf( "refresh Contact response %s\n",response);
                int count=0; 
    
    
    
                while(result!= NULL ) {
                 
                 count=count+1;
    
                   if(strstr(result,":/")!=NULL) {result=NULL;continue;}
    
                if(count>0)
                {     	
                  char **ref;
                  int j;
    	      ref=g_strsplit(result,":",-1);
                  
    char *one="",*two="",*three="",*four="",*five="";
                  for(j=0;j<7;j++)
                  {
    
    
                   if(strstr(ref[j],"one")!=NULL)
    		{
                    char **split1;
    		split1=g_strsplit(ref[j],"=",2);
                    one=split1[1];
    		printf("%s\n",split1[1]);
                    
    		}
                    else if(strstr(ref[j],"two")!=NULL)
    		{
                    char **split2;
    		split2=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split2[1]);
                    two=split2[1];
                    
    		} 
                    else if (strstr(ref[j],"three")!=NULL)
    		{
                    char **split5;
    		split5=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split5[1]);
                    three=split5[1];
    		}  
                    else if(strstr(ref[j],"four")!=NULL)
    		{
                    char **split4;
    		split4=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split4[1]);
                    four=split4[1];
    		} 
                    else if(strstr(ref[j],"five")!=NULL)
    		{
                    char **split3;
    		split3=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split3[1]);
                    five=split3[1];
    		}
                    else {} 
                   
                  }
                   fprintf(appenddatabase, "__BEGIN_\n"); 
                   fprintf(appenddatabase, "%s\n", one);
                   fprintf(appenddatabase, "%s\n", two);
                   fprintf(appenddatabase, "%s\n", three);
                   fprintf(appenddatabase, "%s\n", four);
                   fprintf(appenddatabase, "%s\n", five); 
                } 
                result = strtok( NULL, delims );
    
                }
    
    
             fclose(appenddatabase);
    
    
    }
    
    int
    main(int argc, char *argv[])
    {
      gtk_set_locale ();
      gtk_init (&argc, &argv);
    
    write_data();
    
       gtk_main ();
       return 0;
    }
    save it as one.c
    and compile
    gcc one.c -o one `pkg-config gtk+-2.0 --cflags --libs`

    i used some gtk functions here.

    i know now you are clear about this

    please help me

    thank you in advance

  4. #4
    Lean Mean Coding Machine KONI's Avatar
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    Luxembourg, Europe
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    You're already using strtok() but unfortunately only with the '\n' delimiter. Instead, why don't you use it a little more advanced:

    1. split your input using the delimiter ':', this will give you a sequence of "option=value" items (as long as neither option nor value contains the ':').

    2. split your sequence of "option=value" with the delimiter '=' which will give you the 2 items option and value

    3. print the value corresponding to your options.

    The whole thing shouldn't take more than .... 10 lines max.

  5. #5
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    Wow! That's a boatload of code!!

    I don't mean to be unkind, but it seems to be suffering from the all too familiar "Rube Goldberg" effect.


    Let's look at the problem again:
    ID=123ne=a:two=a@yahoo.com:three=789:four=:five=123 ID=123ne=aa:two=aa@yahoo.com:three=:four=1111111111:five =
    :/

    i would like to truncate this write in a file (file.txt) as
    Code:
    //begin
    a
    a@yahoo.com
    789
    
    123
    //begin
    aa
    aa@yahoo.com
    
    11111111
    //begin
    What I was thinking of was just two while loops:

    Code:
    While (there are more char's to be looked at in the string)  {
       ch = next char.
       if (ch == '=')
             while (1)  {  
                  (ch2 = next char in the string 
                  if ((ch2 != ':') && (ch2 != NULL))
                      write ch2 to the file;
                  else 
                      break;
             }
    }
    The loops could be for loops working from 0 to strlen(string) - 1.

    I'm sure the half-code above is incomplete, but I hope it conveys my thoughts on this. I don't think you want "one" "two" --> "seven", etc. Make it something generic so it will handle any number of entries, and at the same time, make it as simple, small and clear as possible.

    Adak

  6. #6
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    thank you for quick replay

    Quote Originally Posted by KONI View Post
    You're already using strtok() but unfortunately only with the '\n' delimiter. Instead, why don't you use it a little more advanced:

    1. split your input using the delimiter ':', this will give you a sequence of "option=value" items (as long as neither option nor value contains the ':').

    2. split your sequence of "option=value" with the delimiter '=' which will give you the 2 items option and value

    3. print the value corresponding to your options.

    The whole thing shouldn't take more than .... 10 lines max.
    no am unable to write the code in 10 lines

    can anybudy rewrite the code please

    thank you in advance

  7. #7
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    No, I couldn't write the program, I don't use that compiler and don't have those header files. More importantly, you get better at programming if you practice - like anything else.

    I know it's time consuming and it can be frustrating, but I believe you have two ways of doing this program, laid out before you.

    Adak

  8. #8
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    thank you for quick replay

    Quote Originally Posted by Adak View Post
    No, I couldn't write the program, I don't use that compiler and don't have those header files. More importantly, you get better at programming if you practice - like anything else.

    I know it's time consuming and it can be frustrating, but I believe you have two ways of doing this program, laid out before you.

    Adak
    thank you for boosting.

    i succeeded.
    but still having a problem
    it will not printing
    fist "five"(i.e. 123),and it is printing remaining "five".

    whats the problem.

    can you please help me .

    thank you in advance

  9. #9
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    Could it have anything to do with the odd numbering in the code?

    Code:
    if(strstr(ref[j],"one")!=NULL)
    		{
                    char **split1;
    		split1=g_strsplit(ref[j],"=",2);
                    one=split1[1];
    		printf("%s\n",split1[1]);
                    
    		}
                    else if(strstr(ref[j],"two")!=NULL)
    		{
                    char **split2;
    		split2=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split2[1]);
                    two=split2[1];
                    
    		} 
                    else if (strstr(ref[j],"three")!=NULL)
    		{
                    char **split5;
    		split5=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split5[1]);
                    three=split5[1];
    		}  
                    else if(strstr(ref[j],"four")!=NULL)
    		{
                    char **split4;
    		split4=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split4[1]);
                    four=split4[1];
    		} 
                    else if(strstr(ref[j],"five")!=NULL)
    		{
                    char **split3;
    		split3=g_strsplit(ref[j],"=",2);
    		printf("%s\n",split3[1]);
                    five=split3[1];
    		}
                    else {} 
                   
                  }
    I can't run your program, so you'll have to settle for my idea's on this, only.

    Adak

  10. #10
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    thank you for quick replay

    sorry.
    i forgot some code.
    actually this is the response
    Code:
    char *response="LIST=SUCCESS:ID=123:one=a:two=a@yahoo.com:three=:four=456:five=666\nID=123:one=aa:two=aa@yahoo.com:three=22222222:four=:five=0000000000\n:/";
    there is an extra ":" in first line so,
    the first "five"(i.e. 666) is not printing.

    can you please help me in this way

    thank you in advance

  11. #11
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    Quote Originally Posted by munna_dude View Post
    sorry.
    i forgot some code.
    actually this is the response
    Code:
    char *response="LIST=SUCCESS:ID=123:one=a:two=a@yahoo.com:three=:four=456:five=666\nID=123:one=aa:two=aa@yahoo.com:three=22222222:four=:five=0000000000\n:/";
    there is an extra ":" in first line so,
    the first "five"(i.e. 666) is not printing.

    can you please help me in this way

    thank you in advance
    Above the loop that has you checking each char, put a while loop into your code. Conceptually, something like this:

    Code:
    /* n is an int, and you may need to use the ASCII value of '=', instead of '=' (which is 61) */
    while ((n = getchar()) != '=');  /* gets char's and converts to int's until it reaches an equal sign. */
    Note the double (( before the n, and a single extra ) after the getchar, as well as the ; at the end of the compact while statement.

    This is not the best answer to your needs, but it may be ONE answer, in this case.

    Adak

  12. #12
    Frequently Quite Prolix dwks's Avatar
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    Code:
    /* n is an int, and you may need to use the ASCII value of '=', instead of '=' (which is 61) */
    No, you never have to. In C, character literals are actually int values anyway, but even in C++, where they are chars, you don't have to, because it's casted implicitly.
    dwk

    Seek and ye shall find. quaere et invenies.

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