i want to find factors of any given number. i am trying in the following way..how far is it right?
Code:for(i=1; i<=num; i++) { if(num%i==0) printf("Factor = %c",i); }
i want to find factors of any given number. i am trying in the following way..how far is it right?
Code:for(i=1; i<=num; i++) { if(num%i==0) printf("Factor = %c",i); }
why do you use %c format?
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
Hey,
If u r getting ur desired results then its right else wrong. what to worry about.
S_ccess is waiting for u. Go Ahead, put u there.
Works for me approach is not good enoughIf u r getting ur desired results then its right
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
If you think about it, you only have to check for factors until sqrt(n). Beyond that point, any factors you find you already found (as long as you print them). Something like this:
Just a suggestion.Code:for(x = 1; x*x < n; x ++) { if(n % x == 0) { printf("Factor: %d\nFactor: %d\n", x, n/x); } }
dwk
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sorry, there should be %d, not %c. But, thank you DWKS too for letting idea to minimize the iterations.Originally Posted by javani
