a little problem in a basic "if" program
hello everyone,
i have a little problem in a very basic program.
this is the code
by the way,Code:#include<stdio.h> main() { int n; printf("please could you enter an integer to verify it\n"); scanf("%d",&n); if(n>=0); { printf("this is a positive integer\n"); getchar(); } if(n<0); { printf("this is a negative integer\n"); getchar(); } }
what is the difference between " main()" and " int main()" and "int main(void)
You forgot to say what the problem is.Originally Posted by elton_fan
(1) and (2) are semantically the same, except (1) is stupider.
(1) and (2) say main() takes a variable number of arguments, (3) says it takes none.
System: Debian Sid and FreeBSD 7.0. Both with GCC 4.3.
Useful resources:
comp.lang.c FAQ | C++ FQA Lite
What's the difference between... > main() / void main() / int main() / int main(void) / int main(int argc, char *argv[]) :
http://faq.cprogramming.com/cgi-bin/...&id=1043284376
And what is the problem?
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
i thought that you were trying it in order to discover it.
the problem is that whenever you write a number it shows the boths statments means " it's negative and positive too"
Look at those ; at the end of your if statements - they mean "do nothing".
The code in the braces happens anyway.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
oh thank you salem
