Thread: smallest int problem

I'm to write a program that finds the smallest of several intagers. the first vaulue read specifies the number if values remaing for caculation.

here is my code that seems to work put gives me a long negitive number everytime.

Code:

#include <stdio.h>

int main() // start execution
{
	int enter; // the number that determains  specific vaulues remaining
	int counter = 1; // counter used in while
	int number ; // numbers to be entered
	int little; // saves the littlest ineger
	int compare; // used to compare numbers

	printf ("Please Enter how many sequences:\n");
	scanf  ("%d", &enter);

	while( counter <= enter ) // numbers to be entered until = enter
	{
		printf ("Please enter a  positive digit:\n");
		scanf  ("%d", &number);

		number = compare;	
	 
     if (number <= compare){ // if stores the littlest int
			little = number;
				
		} // ends if
		counter++; // counter addition
			
		
	} //ends while

	printf ("Our smallest number is %d.\n", little);

	return 0; // program ended correctly
} // end main

thanks,
joe

Code:

		number = compare;	
	 
     if (number <= compare){ // if stores the littlest int
			little = number;
				
		} // ends if
		counter++; // counter addition
			
		
	} //ends while

Here you set number to compare each time. Your compare number is unitialized, thus is garbage. You'll need to do something like have the user enter one number outside the loop to set as compare. Or, you could set compare to the max int 0x7fffffff.

EDIT: Bummer, beaten.

i'm sorry i meant to type

Code:

compare = number;

hope that makes sense now
but i've been known to be way off before. lol

But that is still wrong.

ok but how would i go about setting anumber outsdie this loop to be entered

salem i did change it and it aways give the answer of the last number i entered

Code:

printf("Please enter a positive digit:\n");
scanf("%d", &compare);
enter--;
	while( counter <= enter ) // numbers to be entered until = enter
	{
		printf ("Please enter a  positive digit:\n");
		scanf  ("%d", &number);

ok here i tried new code

Code:

#include <stdio.h>

int main() // start execution
{
	int enter; // the number that determains  specific vaulues remaining
	int counter = 1; // counter used in while
	int number ; // numbers to be entered
	int little; // saves the littlest ineger
	int compare; // used to compare numbers

	printf ("Please Enter how many sequences:\n");
	scanf  ("%d", &enter);

	printf("Please enter a positive digit:\n");
    scanf("%d", &compare);
    enter--;

	while( counter <= enter ) // numbers to be entered until = enter
	{
		printf ("Please enter a  positive digit:\n");
		scanf  ("%d", &number);

		compare = number;	
	 
     if (number <= compare){ // if stores the littlest int
			little = number;
				
		} // ends if
		counter++; // counter addition
			
		
	} //ends while

	printf ("Our smallest number is %d.\n", little);

	return 0; // program ended correctly
} // end main

i still get the amswer of whatever number i last promted to enter

thank you all so far for your help

And you still aren't reading the posts that Salem and I made LONG AGO: (spoon feeding time)

Code:

	while( counter <= enter ) // numbers to be entered until = enter
	{
		printf ("Please enter a  positive digit:\n");
		scanf  ("%d", &number);

		compare = number;

Originally Posted by Almost Salem

What does this code do?

i see but even if i remove this from the code and then recompile it it still hase the effect of saying

Code:

Our smallest number is "whatever the last number i entered"

so if i tell it 3 on sequence then
lets say first promt i enter 9 
second i enter 1 
and third i enter 5 
five will be the answer as the smallest number

i need to know why its alway printing the last nember i entered as the answer

Remove little from your source. Then, in the if statement, set compare in place of little.

thank you thank you thank you kennedy and salem
i guess i over thought this one and had to many int's lol
and had everything equaling
joe