gets() ignored

I have a problem with gets function. I've put gets as a statement for a switch case, which is inside a loop. This gets seems to get ignored everythime i run my program. What have I done wrong?

Code:

do
	{
		printf("Your choice: ");
		scanf("%d",&menu);

		switch(menu)
		{
		case 1:
			printf("Enter command name to look up: ");
			gets(input);
			printf("aaa\n");

Basically, when i choose menu 1, the output is:

Your choice: 1
Enter command name to look up: aaa
Your choice:

the first mistake that u have done in your programming life is using gets. Why still people use gets. Read FAQ. gets is dangerous. Look at this link.

Gets is bad

Dint you see your compiler warning message " *** gets() is dangerous ***"

instead use fgets()

ssharish2005

ummm, i tried fgets but it doesnt make any difference.

Code:

do
	{
		printf("Your choice: ");
		scanf("%d",&menu);
		
		switch(menu)
		{
		case 1:
			printf("Enter command name to look up: ");
			fgets(input,15,stdin);

The output is still:
Your choice: 1
Enter command name to look up: Your choice:

Help please...

well this is a very coomon questin on the board. But here u go the solution.

Code:

void clear_buffer(void)
{
     int ch;
     while((ch=getchar()) != '\n' && ch != EOF);
}

the problem with you is your scanf(). When u read the value from the user and press enter. Scanf leaves you '\n' in your buffer. you got to clear that. To clear you input buffer use the above function. Call this function after your scanf. that would solve your problem.

Search the form about this issue.

ssharish2005

it worked
thx

Or drop using scanf() and use fgets() to real ALL input.

Then use sscanf() or any other conversion which works on strings in memory to do the rest of the work.