string(pointer to function)

Code:

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#include <stdio.h>

void split_name(char  *a[], char  *b[], char  *c[]);

int main(void)
{
    static char  *Name[2]={"Justin","Barnes"};
    char  *firstname[1];
    char  *secondname[1];
   
    split_name(Name,firstname,secondname);
}

void split_name(char  *a[], char  *b[], char  *c[])
{
  int i=0;
 
                do
                {
                    b[1] = a[i];
                        ++i;
                      c[1] = a[i];
               
                }while(i>0);
    printf("%s %s",*b,*c);
  getchar();
}

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My question is sould i use a <- to take the valuable from a[i] to b and c .but then i get an error because of 1 and when i leave it like this i get an compile error soo im wondering how could i take the teo names from array a to b and c..?

I'm sorry there are just so many things that are *way* off. I suggest you to go back learning arrays and then pointers because there's absolutely nothing right in your code.

Please try to keep your replies helpful and considerate.

I mean.. geez even if we tell him what to change, he won't understand why and he'll make the same mistakes over and over again. Obviously, there's something that's not been understood there.

Edit: Besides, I think it would be more discouraging than anything to point him all the mistakes.

For the start - what this loop should do:

Code:

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int i=0;
do
{
  //code
  ++i;
}while(i>0);

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?
it runs infinite (actually till the overflow occurs and i is back to 0)
Do you mean it? Don't think so...
Start fixing simple things

Wait, is all you want to do to have firstname = "Justin", secondname = "Barnes"?

Code:

---

#include <iostream>

int main(void)
{

    static char  *Name[2]={"Justin","Barnes"};
    char  *firstname = Name[0];  // "Justin"
    char  *secondname = Name[1]; // "Barnes"

    std::cout << firstname << " " << secondname << std::endl;
   
}

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Q: How can I use statically- and dynamically-allocated multidimensional arrays interchangeably when passing them to functions?

http://c-faq.com/aryptr/ary2dfunc3.html

Code:

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static char  *Name[2]={"Justin","Barnes"};

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correct if I am wrong, but from what I have read Name is a pointer yet the array is allso called Name? The array is defined and so is the memory adresses.

Quote:

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Name is a pointer

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yes

Quote:

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the array is allso called Name

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yes

Quote:

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The array is defined

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Yes

Quote:

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and so is the memory adresses.

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here I'm stuck. What do you mean?

I just donest make sense to do this, I cant rap my head around why you would do this. What is the purpose of the array with a pointer when its pointing to the same location that the pointer is also located. In general theory or atleast in my understanding its not logical correct and superfluous. I got the impression from the tut's on this site that an array is like a storage box and that a pointer is another storage box that when the usser opens litteraly points/brings/quarrys/ and brings you to the memory location of the array. From there the user can manipulate the array and such. I hope what I am saying makes some sort of sense, oh the fun of programming at 16.

I would compare the pointer to the localization of the box (i.e. aisle number, sub-section..) but you are correct, KoG Metalgod.

Quote:

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pointer is another storage box

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No pointer is not a "box", it does not provide a memory to store a value, it just points to some location in the memory... This location could be available or could not be available to the program to store there the data...

Code:

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char* ptr; //this pointer is not initialized - it cannot be used
char arr[10]; //this is array, it provides a place for storing 10 bytes, arr can be used as pointer to the first element
//but it cannot be changed like arr++;
ptr = arr;//now ptr points to the first element of the array and can be used
*prt = 'A'; //now we are accessing this first element storing there some data
ptr++; //now we changing the pointer so it is pointing to the second element of the array
*ptr='B'; //see above
arr[2] = 'C';//and now we access the 3rd element of the array using its name

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