Multiple functions

I am trying to create a program with multiple functions before the main function. I am trying to use an array and use the element data in all the different functions but I am getting an error saying that the int wasn't declared. How do i use the same array data throughout all the funtcions?

Pass the value around using a pointer. Or use a global. Or something wierd that the OS supplies you with.

>> I am trying to create a program with multiple functions before the main function

You can declare the functions before main (or in a header) and then define the function wherever you like

Code:

void foo(int * array, int size); // function
void bar(int * array, int size); // prototypes

int main() { int intarray[5280]; foo(intarray); bar(intarray); return 0; }

void foo(int * array, int size) 
{ /* do stuff with array; array[index < size] = stuff */ }

void bar(int * array, int size) 
{ /* ditto */ }

Perhaps if you supplied code we could help you better?

Code:

int array (int size, int i)
 {
	int a[5];
	printf(" enter the 5 elements for the array.\n");
	for (i = 0; i <= 4; i++)
	{
		scanf("%d ", &a[i]);
	}
printf("%d, %d, %d, %d, %d\n", a[0], a[1], a[2], a[3], a[4]);
	return a[i];
}

int add(int a, int size)
{
	int sum;
	int a[5];
	sum = a[0] + a[1] + a[2] + a[3] + a[4];
	printf("The sum is: %d\n", sum);
	return sum;
}

This is just 2 functions. trying to get the data entered into the first one to be used for the second. I know it is very flawed and it is for a class so only requesting hints, not code.

Try to see if you can use the logic I provided in my post for your purposes

Code:

int array(int * array, int size); // function
int sum(int * array, int size); // prototypes

int main() { int intarray[5280]; array(intarray, 5280); int sum = add(intarray, 5280); return 0; }


// Arguments: array, size of array
// Returns: non-zero if successful

int array(int * array, int size) 
{ /* exactly what you did essentially, but &array[i] */ }


// Arguments: array, size of array
// Returns: sum of elements in array

int add(int * array, int size) 
{ /* ditto */ }

I am putting the funtions before main(), only the function calls are being put into main(). I get the error:

error C2109: subscript requires array or pointer type

for my array in the second function when I am trying to use the data entered into the first function. I have cleaned up the first function so it works right but I am trying to get the second function to use the data and the same array in the first one. Will work on it a little more tonight then hit it again in the morning.

You can't pass and return arrays like you can with integers.

So you have to decide who is in overall charge (say main), and let it declare the array. Then you pass that array (as a pointer) to all the interested functions to do their bit.

Code:

void input (int a[], int size)
{
	printf("enter the %d elements for the array.\n", size );
	for (i = 0; i < 5; i++)
	{
		scanf("%d ", &a[i]);
	}
}

int add(int a[], int size)
{
	int i, sum = 0;
	for ( i = 0 ; i < size ; i++ ) sum += a[i];
	return sum;
}

int main ( ) {
	int arr[5];
	input(arr,5);
	printf("The sum is: %d\n", add(arr,5) );
	return 0;
}

Unfortunately I cannot have any variables or arrays declared in the main() function. The only thing I can use in main are the function calls. I also don't understand how arr[5] can be declared for a[]. Granted that code works, although I cannot use it.

Originally Posted by rculley1970

Unfortunately I cannot have any variables or arrays declared in the main() function. The only thing I can use in main are the function calls. I also don't understand how arr[5] can be declared for a[]. Granted that code works, although I cannot use it.

what sort of problem is that, whyy variables shouldn't be declared in main.

Well, any way u could do something like this

Code:

void input ()
{
	int a[5]
                printf("enter the %d elements for the array.\n", size );
	for (i = 0; i < 5; i++)
	{
		scanf("%d ", &a[i]);
	}

                 printf("The sum of all numbers is %d", add(a,5);
}

int add(int a[], int size)
{
	int i, sum = 0;
	for ( i = 0 ; i < size ; i++ ) sum += a[i];
	return sum;
}

int main ( ) {
	printf("The sum is: %d\n", add(arr,5) );
	return 0;
}

Note: The array no more exist after the control comes out of the input function

ssharish2005

Please revise your code sharish, it is incomplete and confusing.

Do you have some interface you must implement?If not ,as Tonto already said , a global array would do the work.

Code:

 
int array[SIZE] ;/* the global array*/

int some_function( void ) ; /*prototyopes */

int main( void )
{
   /*this and that*/

  return 1;
}

Be careful with the global array though...It is not considered as the best programming practise

Usually one returns 0 from main() to indicate success.

There's no reason to use a global variable -- passing an array between functions isn't too hard. Have a look at another example:

Code:

#include <stdio.h>

void print_array(int *array, int elements);

int main(void) {
    int array[] = {1, 2, 3, 4, 5};

    print_array(array, sizeof(array)/sizeof(*array));
}

void print_array(int *array, int elements) {
    int x;

    for(x = 0; x < elements; x ++) {
        printf("%d\n", array[x]);
    }
}

(Note that I would use a variable of type size_t for the number of array elements in a real program.)

Thanx for the tips dwks,
As far as the globlal array is concerned , I think it fits best in the specific situation. I mean it seems a bit strange that he is supposed not to declare any variables in main , just calling the functions so i assumed that they should use a global array.

Right, I missed that criteria. A global array is the best idea, then.

I appreciate everyones help, I just got on and am looking at the help and working on it now. I don't want to go too far into explaining since it is for a class so I just want hints provided as I don't want to get busted for plagerism. I will be outlining that I recieved help from this board in my discussion on the project. I will look into the global array.