can someone explain to me what is fgets()

[Meshal]

if we compile and execute this program

#include <stdio.h>

int main ( void )
{
  char buffer[BUFSIZ];

  printf ( "Enter a string: " );
  if ( fgets ( buffer, sizeof buffer, stdin ) != NULL )
    printf ( "|%s|\n", buffer );

  return 0;
}

the output will be :

|test
|

can i know why ?!!
because in the code there is no newline char btw. %s and the |

[CornedBee]

I won't explain what fgets is; a reference can do that better.

Your problem is that you write a line of input and hit enter, which inserts a newline into the stream. fgets() reads that newline and places it in the buffer. Thus, when you print the buffer, you get the newline.

[Meshal]

thanks .

[ssharish2005]

avoid that by

#include <stdio.h>

int main ()
{
  char buffer[BUFSIZ];
  char *p;
  
  printf ( "Enter a string: " );
  if ( fgets ( buffer, sizeof buffer, stdin ) != NULL )
  {
    p = strchr(buffer,'\n');
    *p='\0';    
    printf ( "|%s|\n", buffer );
  }
  
  getchar();
  return 0;
}
/* my output
Enter a string: This is a test
|This is a test|
*/

ssharish2005

[CornedBee]

Except that you need to test p for non-NULL, otherwise you get an access violation if the string does not contain a '\n' (usually because the line is longer than the buffer).

[ssharish2005]

Except that you need to test p for non-NULL, otherwise you get an access violation if the string does not contain a '\n' (usually because the line is longer than the buffer).

#include <stdio.h>

int main ()
{
  char buffer[BUFSIZ];
  char *p;
  
  printf ( "Enter a string: " );
  if ( fgets ( buffer, sizeof buffer, stdin ) != NULL )
  {
    p = strchr(buffer,'\n');
    if(p != NULL)
          *p='\0';    
    printf ( "|%s|\n", buffer );
  }
  
  getchar();
  return 0;
}
/* my output
Enter a string: This is a test
|This is a test|
*/

code updated

ssharish2005