Thread: Need help from the gurus. homework

here is the question posed.

# Ask the user to enter a digit between 0 and 9. Have the program print out the digit in words, for example:

Enter a digit between 0 and 9: 4
You entered the number four

Assume that the user will enter only a single digit. The user may accidentally enter a single character, and this should generate an error message.

Code:

#include <stdio.h>
int main()
{
    int num;  
    printf("Please enter a digit from 0 through 9\n");
    scanf("%d,",&num);
    
    if (num == 0)
       printf("The number you have typed is zero.\n");
    else if (num == 1)
        printf("The number you have typed is one.\n");
    else if (num == 2)
        printf("The number you have typed is two.\n");
    else if (num == 3)
        printf("The number you have typed is three.\n");
    else if (num == 4)
        printf("The number you have typed is four.\n");
    else if (num == 5)
        printf("The number you have typed is five.\n");
    else if (num == 6)
        printf("The number you have typed is six.\n");
    else if (num == 7)
        printf("The number you have typed is seven.\n");
    else if (num == 8)
        printf("The number you have typed is eight.\n");
    else if (num == 9)
        printf("The number you have typed is nine.\n");
    else
        printf("You have selected to not follow the instructions therefore an error has occurred.\n"); 
        
        
        return 0;
}

when i type in other integers greater then 9 i display the error message, however when i type a character i return the your number is two.

let me know where i went wrong.

Go through the following code. If you have any questions, please don't hesitate to ask!

Code:

#include <stdio.h>
#include <ctype.h>
int main()
{
  int num;  
  printf("Please enter a digit from 0 through 9\n");
  num=getchar();    
  if (isdigit(num))
  {    
    if (num == '0')
      printf("The number you have typed is zero.\n");
    else if (num == '1')
      printf("The number you have typed is one.\n");
    else if (num == '2')
      printf("The number you have typed is two.\n");
    else if (num == '3')
      printf("The number you have typed is three.\n");
    else if (num == '4')
      printf("The number you have typed is four.\n");
    else if (num == '5')
      printf("The number you have typed is five.\n");
    else if (num == '6')
      printf("The number you have typed is six.\n");
    else if (num == '7')
      printf("The number you have typed is seven.\n");
    else if (num == '8')
      printf("The number you have typed is eight.\n");
    else if (num == '9')
      printf("The number you have typed is nine.\n");
  }
  else
    printf("You have selected to not follow the instructions therefore an error has occurred.\n"); 
    
  return 0;
}

As a further exercise, try making the code more compact.

> Sad i am a nuclear engineering major but c kicks my but
What does a nuclear engineer (should we all be afraid at this point?) want with a language which isn't rated for such safety critical applications like nuclear installations?

This could be bad

*contemplates the irony of his own avatar...*
If you're dyslexic, are you unclear about nuclear?

Well my friend who posted there code the issue is the last Else if statement is var ==9 so you have a few things you can do. A just simply add a loop. Inside all the Else If statements place a break inside all the statements. Then add an Else with a Printf saying retype the number and as a result you reloop. Another way is just too simply say but have it wrong n<=9. a little back story the reason why when you typed in a char you received an error is because you scanf is looking for a decimal "scanf("%d,",&num);" and in ANSI C all chars are trying ints example A==1 B==2 (also caps are greater value then lower case A>a). To avoid this error to a degree is to have the code gets(num) then num1 = atoi(num). This will take any int or char and turn it into an int. Lets say you typed in 12334 and did not have atoi what can happen is the computer looks at the number like a solid string "12334". Sorta like you zip code but if you atoi the int string it will break it up to read 12,334 and from there you can apply you int.

Stop hijacking threads, posting opinionated nonsense, and generally acting like an idiot.

That would be like Chernobyl/Matrix

"nuclear about unclear"? What on earth is Salem talking about

Thanks again everyone and honestly i would be scared if a reactor was only electronically controlled chernobyl 2007 haha

That's an excellent idea, actually. It's relatively harder to program a computer to perform crazy, random, unsanctioned runtime experiments without safety precautions, than to allow dyslexic technicians to do the same.