Arrays as function arguments!

Hi all!!

I have a problem. I have to write a program that initialises a 2 dimensional arrayof double and uses a function to copy the sub-arrays of this 2 dimensional function one-by-one in to a seperate array.

please help. ive spent all day on this and wrote so many variations.
I can copy a 2 dimensional array within the main function, like so...

#include <stdio.h>
#define SIZEA 2
#define SIZEB 4

Code:

main()
{
	int i, j;
      double destination2[SIZEA][SIZEB];
      double source[SIZEA][SIZEB]=
	  {
		  {5, 3, 6, 7},
		  {3, 15, 12, 4}
	  };

	   for(i=0; i<SIZEA; i++)
	   {
			for(j=0; j<SIZEB; j++)
			{
			destination2[i][j]= source[i][j];
			printf("%.2f\n", destination2 [i][j]);
			}
			printf("\n");
	   }

}

but this isnt what the question asks for and im really stuck.

Thanks in advance

Stuart

An easy rule to remember is copy/paste

Code:

void copyArray ( double destination2[SIZEA][SIZEB], double source[SIZEA][SIZEB] ) {
  // your two loops here
}

Which you would call with

Code:

copyArray( destination2, source );

You can of course rename the formal parameters if you want to, to be more descriptive in the function body.

You can also omit the LEFT-MOST array size as well.

Code:

void copyArray ( double destination2[][SIZEB], double source[][SIZEB] ) {
  // your two loops here
}

thanks a bundle m8!!!