Thread: Help with a simple loop...

My mistake! I thought it checked for the pin in the while loop. However, break will also do nothing, going straight to the break out of the switch statement. Thus you need to get the pin in the while loop.

break might work, I was thinking something along the lines of this:

Code:

        for(;;)
        {
             printf( "This is not the correct PIN\n" ) ;
             printf( "Please re - enter your pin\n" ) ;
             scanf( "%d",&pin ) ; //re scan pin
             if(pin == 1234) break;

             printf( "This is not the correct PIN\n" ) ;
             printf( "Please re - enter your pin.You have one attempt left\n" ) ;
             scanf( "%d",&pin ) ; //re scan pin
             if(pin == 1234) break;
             
             printf( "This is not the correct PIN\n" ) ;
             printf( "You must re - start Program\n" ) ;
             scanf( "%d",&pin ) ; //re scan pin
             if(pin == 1234) break;

             printf( "Press 3 to exit\n" ) ;
                 scanf( "%d",&exit) ;
             
             
             break ;
        }// end for

But still, a modified version would be better.

Maybe a more flexible

Code:

int count, max = 5;
for(count = 1; count <= max; ++count)
{
    printf("Enter PIN [attempt %d of %d]: ", count, max);
    scanf("%d", &pin);
    if(pin == 1234)
    {
        break;
    }
    printf("ERROR: PIN incorrect\n");
}

if(pin != 1234)
{
    printf("You have used up all attempts!\n");
    printf("The PIN has been locked\n"); /* whatever */
}