fprintf in void function Not Printing

I have a function call in my main function. It is suppose to be a progress reporter. Each time the function is called, as shown below, the progress is to be printed on the screen.

Code:

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loop_counter(&loop_count, some_constant);

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The function body looks like the following:

Code:

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void loop_counter(long long *loop_count, long long some_constant)
{
*loop_count++;
if(*loop_count % 40000 == 0 || *loop_count == some_constant)
fprintf(stderr,"\r %d %% done ", (long long)(100.0*(double)(*loop_count)/(double)some_constant));
}

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For some reason, nothing gets printed on the screen. Can anyone tell me why this is?

>fprintf(stderr,"\r %d
To print a long long, use either %lld, or if that doesn't work, %I64d.

Code:

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fprintf(stderr,"\r %I64d %% done ", (long long)(100.0*(double)(*loop_count)/(double)some_constant));

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If nothing at all is being printed, then the if condition isn't being met. You would have to show us what loop_counter and some_constant are at this call:
>loop_counter(&loop_count, some_constant);

MSVC 6 doesn't have support for long longs in its standard C library, but Dev-C++ and others do. MSVC treats it like a long, so if you don't exceed the limits of a long, it should work even there.

If I replace

Code:

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loop_counter(&loop_count, some_constant);

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in my main() function with

Code:

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loop_count++;
if(loop_count % 40000 == 0 || loop_count == totalN)
fprintf(stderr,"\r %d %% done ", (long long)(100.0*(double)loop_count/(double)totalN));

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then everything works fine. I don't think the problem is the %d or the long long. The problem is that nothing at all gets printed to the screen.

Based on the code you just posted, then here:
>*loop_count++;
What you really want is:

Code:

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(*loop_count)++;

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Thanks. That did it