Reading integers from a File into an Array

Hey,

Basically for this question, I am reading elements of a matrix from a text file. Now, the matrix is an upper triangular matrix, meaning the elements under the main diagnol are zero.

eg

1 2 3 4
0 5 6 7
0 0 9 1
0 0 0 2


Heres the problem. In the text fle, the matrix is stored in "efficient form," meaning the anything below the main diagnol (the zeros) are not listed.

Now I am trying the read in the efficient matrix text file and display it on the screen WITH the zeros added in. (It is a 6 x 6 matrix in the txt file btw) I have my algorithm...
i = the zero counter (intialized to 0)
j = the integer element counter (intialized to 6)

-print the number of zeros in the i counter (i = 0)
-increment the i counter (i = 1)
-print the number of elements in the j counter from the text file (j = 6)
-decrement the j counter (j =5)
- new line

-print the number of zeros in the i counter (i = 1...print 1 zero)
-increment the i counter (i = 2)
-print the number of elements in the j counter from the text file ( j = 5... print the next 5 elements)
-decrement the j counter (j = 4)
- new line

....and so on (the i and j variables dont match my code exactly...)

I think my code is correct except for the part of reading in the text file in the element[] array (in bold below). Im not too sure on how to do that. If you could help me out with that, Id really apprecieate it!

Thanks

Code:

#include<stdio.h>
#include <stdlib.h>

viewM1();

main()

{
	int choice;

	printf("\nThis program allows you to multiply two matricies in a NON-EFFICIENT format\n\n");
	printf("Please choose from one of the following options:");
	printf("\n1 - See Matrix #1");
	printf("\n2 - See Matrix #2");
	printf("\n3 - Multiply Matrix #1 and Matrix #2");
	printf("\n4 - Exit\n");
	printf("\nOption Number: ");

	scanf("%d", &choice);

	if (choice == 1)
		viewM1();

return 0;	
}


viewM1()
{
	int elements[22], i, j, k, l, counter = 0, a = 0;
	FILE *file_ptr;
	file_ptr = fopen("matrixA.txt", "r");
	if (file_ptr == NULL)
		{
		printf("Sorry! The File could not be opened!\n");
		exit(1);
		}
	else
		{
		while (!feof(file_ptr))
		fscanf(file_ptr, "%d", &elements[a]);
		a = a + 1;
		}
		
			for (i = 0; i <= 5; i++)
			{
				for (j = 0; j < i; j++)
				{
					printf("0");

					for (k = 6; k > 0; k--)
					{
						for (l = 0; l <= k; l++) 
						{
							printf("%d", elements[counter]);
							counter++;
						}
					}
				}
					printf("\n");
			}

		


		

	fclose(file_ptr);
	return 0;
}

Originally Posted by bobby19

Code:

while (!feof(file_ptr))
		fscanf(file_ptr, "%d", &elements[a]);
		a = a + 1;

Where are the braces of while?

Whoops...ahhh totally forgot them.

Added them in, but still wild results coming out...Is that the proper way to read the elements into the array?

Thanks

Code:

while (!feof(file_ptr))      /* http://c-faq.com/stdio/feof.html */
   fscanf(file_ptr, "%d", &elements[a]);
   a = a + 1;      /* what is the role of a? */

> int elements[22],
Furthermore, by my count your text file has 21 numbers in it. Assuming that a row in a six-by-six matrix has six numbers, there is no way (efficient or not) that 21 numbers fills half the matrix. 21 doesn't even have six as a factor.

[edit]
Matrices must be my one true weakness.

-15 1 -12 -2 -2 3
0 -9 -12 -4 -14 -11
0 0 -13 10 -14 -2
0 0 0 10 -1 -2
0 0 0 0 6 5
0 0 0 0 0 -11


That would be the matrix in full form. The 21 elements in the text file are basically 6^2 - 15.

ahh its not showing up properly...but that is the format

You're printing it wrongly. Try using:

Code:

	for (i = 0; i <= 5; i++)
	{
		for (j = 0; j < i; j++)
		{
			printf("%4d ", 0);
		}
		
	
		for ( ; j<=5; j++)
		{
			printf("%4d ", elements[counter]);
			counter++;
		}
		
		printf("\n");
	}

Thank you!

Originally Posted by bobby19

Whoops...ahhh totally forgot them.

Added them in, but still wild results coming out...Is that the proper way to read the elements into the array?

Thanks

Now that's what happens when you don't put braces around one-line statements. Later you want to add one more line and you've got a problem.

Hi again,

1 more problem now....

I changed the location of where the files are scanned into the main function so that I can pass the arrays on the matrix multiply function when need be. I also added in a 2D array which stores the enitre matrix (matrixA2D and matrixB2D - so that I can matrix multiply later on)

When I enter option 1 to view Matrix 1, it goes to the 5th row of the array and abruptly stops and I get an error. I took out the operation where I fill in the elements for the 2D array, and then it works. Im not sure what the problem is though. Tracing through the code, it seems like what I have wrote will fill in the elements for the 2D array... Any thoughts?

Code:

#include<stdio.h>
#include <stdlib.h>

void viewM1(int [21]);
void viewM2(int [21]);


void main()

{
	FILE *file_ptrA;
	FILE *file_ptrB;
	int choice;
	int elementsA[21], elementsB[21], counter = 0, a = 0, b = 0;

	file_ptrA = fopen("matrixA.txt", "r");
	file_ptrB = fopen("matrixB.txt", "r");

	while (!feof(file_ptrA))
			{	
			fscanf(file_ptrA, "%d", &elementsA[a]);
			a = a + 1;
			}

	while (!feof(file_ptrB))
			{	
			fscanf(file_ptrB, "%d", &elementsB[b]);
			b= b + 1;
			}

	fclose(file_ptrA);
	fclose(file_ptrB);


	printf("\nThis program allows you to multiply two matricies in a NON-EFFICIENT format\n\n");
	printf("Please choose from one of the following options:");
	printf("\n1 - See Matrix #1");
	printf("\n2 - See Matrix #2");
	printf("\n3 - Multiply Matrix #1 and Matrix #2");
	printf("\n4 - Exit\n");
	printf("\nOption Number: ");

	scanf("%d", &choice);

	if (choice == 1)
		viewM1(elementsA);
	else if (choice == 2)
		viewM2(elementsB);
}


void viewM1(int matrixA[])
{
	int i, j, counter = 0, a= 0, matrixA2D[6][6];
		
	for (i = 0; i <= 5; i++)
	{
		for (j = 0; j < i; j++)
		{
			printf("%4d ", 0);
			matrixA2D[i][j] = 0;
		}
		
	
		for (; j <= 5; j++)
		{
			printf("%4d ", matrixA[counter]);
			matrixA2D[i][counter] = matrixA[counter];
			counter++;
		}
		
		printf("\n");
		
	}

}


void viewM2(int matrixB[])
{
	int i, j, counter = 0, a = 0, matrixB2D[6][6];

		
	for (i = 0; i <= 5; i++)
	{
		for (j = 0; j < i; j++)
		{
			printf("%4d ", 0);
			matrixB2D[i][j] = 0;
		}
		
	
		for (; j<=5; j++)
		{
			printf("%4d ", matrixB[counter]);
			matrixB2D[i][counter] = matrixB[counter];
			counter++;
		}
		
		printf("\n");
	}
		
}

main() returns int. See site FAQ.
Don't use feof() to control while loops. See site FAQ.
You should check that the return value of fopen() isn't NULL.

And then ensure that you access your array only within its bounds.

Code:

		for (; j <= 5; j++)
		{
			printf("%4d ", matrixA[counter]);
			matrixA2D[i][counter] = matrixA[counter];
			counter++;
		}

If you get to 10 or so in matrixA, where are you in matrixA2D? Perhaps you meant matrixA2D[i][j].

Prob Fixed! Thanks a lot for the tips and suggestions. Quick questions about the main function. Our text frequently uses the void return type for main. Is there a specific reason to have an int return type, and then return 0?

Thanks again

main() always returns int, except in very rare and very exceptional circumstances.
Your textbook is made of fail.
There are a few existing threads with further details.

Originally Posted by citizen

Furthermore, by my count your text file has 21 numbers in it. Assuming that a row in a six-by-six matrix has six numbers, there is no way (efficient or not) that 21 numbers fills half the matrix. 21 doesn't even have six as a factor.

Simple maths. For each diagonal the number of elements are:
1 + 2 + 3 + 4 + 5 + 6
>> 1 + 2 + ... + n-1 + n
= n(n+1)/2.
6(6+1)/2 = 21.


By the way, using "x <= 5" in terms of iteration is less clear than using "x < 6". You could then make it more robust by subsituting "x < MATRIX_SIZE" in the future (or even right now, for readability).

You want more compactness? You could use a single char for two digits (direct to binary or translating to valid ASCII characters), and maybe use the highest bit to store the sign. Whazaa.