How to printf for varying variable

This is a discussion on How to printf for varying variable within the C Programming forums, part of the General Programming Boards category; I am trying to pad result with a length of zeros specified by padlength, I'm unsure of how to do ...

  1. #1
    Registered User
    Join Date
    Sep 2006
    Posts
    5

    How to printf for varying variable

    I am trying to pad result with a length of zeros specified by padlength,
    I'm unsure of how to do this since the printf doesn't take this arg..


    Code:
    
    void printConversion(int value)
    {
    	char *result = convert(value);
    	int padLength = 12-strlen(result);
    
    	printf("%d ",value);
    	printf("%0padLengths\n",result);
    }
    
    
    
    char *convert(int value)
    {
    	static char buf[5];
    	itoa(value, buf, 2);
    	return buf;
    }

  2. #2
    Awesomefaceradcore bivhitscar's Avatar
    Join Date
    Apr 2006
    Location
    Melbourne, Australia
    Posts
    210
    The easiest way to do it would be a loop.
    Code:
    for ( i = 0; i < padLength; i++ )
    {
        printf("0");
    }
    it's ironic considerate rarity patron of love higher knowledge engulfs me...

  3. #3
    Just Lurking Dave_Sinkula's Avatar
    Join Date
    Oct 2002
    Posts
    5,006
    Maybe something like this?
    Code:
    void printConversion(int value)
    {
    	char *result = convert(value);
    	int padLength = 12-strlen(result);
    
    	printf("%10d ",value);
    	printf("%0*d%s\n", padLength, 0, result);
    }
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

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