Help with printf

Hi all
I'm having some problems with this code:

Code:

struct Note{
       float duration;
       float ampvalue;
       float pitchvalue;
};

int main()
{
       struct Note *gnote = malloc(sizeof(struct Note));
       noteprepare(gnote, 2);    /*fill *gnote with some data*/
       
       printf("%f   %f   %f\n\n", gnote->duration, gnote->ampvalue, gnote->pitchvalue);
       printf("%f   %d   %f\n\n", gnote->duration, gnote->ampvalue, gnote->pitchvalue);
       return 0;
}

The only output I care about of course is from the printf() with all floats, but I can't figure out why I get weird input from the second printf().
Here is an example of what I get:

Code:

0.250000   2000.000000   587.299988
0.250000   0   26815622315368532000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000000
0000000000.000000.

Or:

Code:

0.000000   2300.000000   659.260010
0.000000   0   -0.000000

The first line of output is exactly what I want, but I don't understand what's going on with the second.
Thanks for your help
PS I'll pose noteprepare() if anyone thinks it will be helpful
PPS I'm using WindowsXP with MinGW

These are not the same.

Code:

       printf("%f   %f   %f\n\n", gnote->duration, gnote->ampvalue, gnote->pitchvalue);
       printf("%f   %d   %f\n\n", gnote->duration, gnote->ampvalue, gnote->pitchvalue);

I think the OP knows that but is wondering why it prints 0 (for a float passed to %d) every time . . . .

Just one point - the float's memory format is different from int's!

E.G. (float)1.0 is verrrrry different from (int)1 in memory.

If %f, printf() thinks that the gnote->ampvalue is a float; If %d, printf() thinks that the gnote->ampvalue is a int.