Thread: arrays of structs

Originally Posted by echo49

hi there
i'm new to C programming, and there's this code i'm trying to get running

What you want is this:

Code:

typedef struct
{
	char word[ SOMESIZE ];
} dictionary;

dictionary dict[749] =
{
    { "account" },
    { "act" },
    { "addition" },
    { "adjustment" },

    //...

    { "wrong" },
};

Arrays of structures can be initialized like other arrays, as above, provided it's done at the time of declaration. Otherwise, if you're trying to copy strings to them, you'll need strcpy or its kin.

Also, you need to either specify a size for your array (the member of the structure), or you need to get rid of it, and use a pointer to a char instead.

Finally...

Originally Posted by esbo

I have been programming for years, but I started at the shallow end!!

And I would never attempt anything as monsterous as that today!!

You're a liar, and are too ........ing stupid to know how to simply initialize an array, and know no C at all. Get off the forum, I'm tired of your lies and misinformation crapping up the C board. I will endevor to get you permenantly banned every chance I get.


Quzah.

You only need to wrap as I did if you're initializing structure elements. Your method using just a multidimensional array is (currently) correct. The braces around each word is because they're structure elements. Like so:

Code:

struct foo {
    int a;
    float b;
    char c;
    char *str;
} arrayoffoo[] =
{
    { 10, 1.23, 'c', "hello" },
    { 55, 3.67, 'x', "goodbye" },
    {  9, 22.0, 'y', "foo bar baz" },

};

The first set of braces, excluding the actual structure definition, wrap up the bounds of the entire array. The nested sets are for each structure. Each structure's elements are grouped by a pair of braces. When you reach the } on the inner set, you know you're at the end of the elements for that structure. When you reach the final }, you've reached the end of the array's elements.


Quzah.