Thread: chessboard simulation

I'm trying to write a chessboard simulation basically the black and white colors are represented by either #'s or spaces


so something like:

Code:

 # # # #
# # # #
 # # # #
# # # #
 # # # #
# # # #
 # # # #
# # # #

my program currently prints:

Code:

 # # # #
 # # # #
 # # # #
 # # # #
 # # # #
 # # # #
 # # # #
 # # # #

the column and row's are both 8 in length.

so basically for each column i do the following:
if (col % 2 == 1)

which either returns a 0 or 1. if it's 0 i put board[row][col] = ' '; otherwise board[row][col] = '#';

Now my problem: I *want* every second row to start off with board[row][col] = '#'; so it looks like a chessboard... Any ideas?

so something like (where 0 = space and 1 = #)
0101010
1010101
0101010
1010101
0101010
1010101
0101010

>> hich either returns a 0 or 1. if it's 0 i put board[row][col] = ' '; otherwise board[row][col] = '#';

Make ' ' and '#' flags or something, and do the same sort of modularity by 2 on row and swap the flags.

Well, you should take the row numbers into accout also.

Starting from row number 1 and column number 1 (left-most square at the top), you see that

Code:

if (row_number*column_number = odd)
 squre_color= white
else /* if the product is even */
 squre_color=black

Hope helps...

I did not compile/run the code, but this may work

Code:

 int row=1, column=1;
while(row<9)
{
    if ((row*column)%2)
       printf("#");
    else
       printf("  ");
   
    column++;
    if (!(column%8))
    {
       row++;
       printf("\n");
    }
}

As I said, i did not try the code and it is possible to get a wierd output!

Well, I didn't compile this, I only want to describe another way, using for and initializing color depending on the number of row.
This will contain for sure some errors, but the idea I think is ok.

Code:

color = ' ';
for (x=a;x<8;x++)
 {
 if ((x%2) == 1) { color =' '} else {color ='#' }; 
  for (y=0;y<8;y++)
   {
    board[x][y] = color;
   if (color=='#') { color = ' '} else { color = '#'; }
   }
 }

-----------------------
http://www.uberum.com

I ended up solving it it seemed confusing at first but i just wrote down the logic in english and it came to me. Basically i got rid of the mod idea and saved the last character in a char (i.e. # or ' ') and kept switching between it and saving to a variable by comparing it to the last character printed. Next in my outer row loop i check this variable and switch between it so it reflects the columns.


Anyway, thanks guys it's always good to know to know how to do it in other ways too..

Good code prelude

I didn't understood following line, can anyone explain(couldn't find it in TC help either)

x = ~x;

where x is unsigned int.