hi,I got a text file,sample of it is below:
dog cat art
cat dog
art
I would like to write a program,to read the file and print out the words,one by one.So the output would be:
dog
cat
art
cat
dog
art
What command to use?I tried to use fgets and fscanf without much sucess.Any guide provided would be much appreciated.
Thanks-Rahul
Post what you tried.Originally Posted by rahulsk1947
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
it prints the last word endlessly.Code:int main(int argc, char* argv[]){ FILE *fp; char a[80]; fp=fopen("z.txt","r"); while(a!=NULL){ fscanf(fp,"%s",a); printf("%s-",a); } }
Understand the function you are calling.
How about checking for success?
Code:#include <stdio.h> int main(void) { static const char filename[] = "file.txt"; FILE *file = fopen(filename, "r"); if ( file ) { char word[80]; while ( fscanf(file, "%79s", word) == 1 ) { puts(word); } } else { perror(filename); } return 0; }
7. It is easier to write an incorrect program than understand a correct one.
40. There are two ways to write error-free programs; only the third one works.*
The "%79s", whats the use of it? (string composed of 79 characters?)
(Excuse me if I replied with a question, im just curious. Hope u'll understand)
Last edited by Xero; 08-24-2006 at 10:06 AM.
It's actually much simpler to use a FSM-style program for this:
Code:1. Read CHAR from INPUT file 2. If CHAR -> [non-whitespace], write CHAR to OUTPUT file and set IS_WORD to TRUE 3. If CHAR -> [whitespace] 4. If IS_WORD is TRUE, write newline to OUTPUT file and set IS_WORD to FALSE 5. If IS_WORD is FALSE, do nothing 6. Go back to (1)
Code:#include <stdio.h> void J(char*a){int f,i=0,c='1';for(;a[i]!='0';++i)if(i==81){ puts(a);return;}for(;c<='9';++c){for(f=0;f<9;++f)if(a[i-i%27+i%9 /3*3+f/3*9+f%3]==c||a[i%9+f*9]==c||a[i-i%9+f]==c)goto e;a[i]=c;J(a);a[i] ='0';e:;}}int main(int c,char**v){int t=0;if(c>1){for(;v[1][ t];++t);if(t==81){J(v[1]);return 0;}}puts("sudoku [0-9]{81}");return 1;}
Xero, please don't hijack threads. And did you do a online search? There are a lot of reference pages for scanf() and its variants.
Code:#include <stdio.h> void J(char*a){int f,i=0,c='1';for(;a[i]!='0';++i)if(i==81){ puts(a);return;}for(;c<='9';++c){for(f=0;f<9;++f)if(a[i-i%27+i%9 /3*3+f/3*9+f%3]==c||a[i%9+f*9]==c||a[i-i%9+f]==c)goto e;a[i]=c;J(a);a[i] ='0';e:;}}int main(int c,char**v){int t=0;if(c>1){for(;v[1][ t];++t);if(t==81){J(v[1]);return 0;}}puts("sudoku [0-9]{81}");return 1;}
I apologise.
It limits the string read to 79 characters. (Excluding the NULL.)
dwk
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